<span>67 24 out of 100 i believe</span>
Answer: x = 156°
Step-by-step explanation:
So it is proven all triangles equal 180° and all straight angles are 180° so
85+71= 156
180-156=24°
but since you are trying to find x (to create the straight angle) and now know the other missing angle is 24°
180-24= 156
x=156°
Answer:
see explanation
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x + 2 is in this form with slope m = 3
• Parallel lines have equal slope
• The slopes of perpendicular lines are negative reciprocals of each other
A
y = -
x - 8 has slope m = - 
3 and -
are negative reciprocals
This line is perpendicular to y = 3x + 2
B
y = 3x - 10 has slope m = 3
This line is parallel to y = 3x + 2
C
y = 2x + 4 has slope m = 2
This line is neither parallel nor perpendicular to y = 3x + 2
Answer:
Hi there!
If you are 15 right now, you would use the expression: 15+12=y
Dimensions are length 20 meter and width 14 meter
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
Given that,
<em><u>A rectangle has width that is 6 meters less than the length</u></em>
Width = length - 6
b = a - 6
The area of the rectangle is 280 square meters
<em><u>The area of the rectangle is given by formula:</u></em>

<em><u>Substituting the values we get,</u></em>

<em><u>Solve the above equation by quadratic formula</u></em>



Since, length cannot be negative, ignore a = -14
<em><u>Thus solution of length is a = 20</u></em>
Therefore,
width = length - 6
width = 20 - 6 = 14
Thus dimensions are length 20 meter and width 14 meter