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lubasha [3.4K]
3 years ago
11

What is the y-value of the vertex of the function f(x) = –(x – 3)(x + 11)?

Mathematics
1 answer:
Mrrafil [7]3 years ago
5 0
Expand
f(x)=-1x^2-8x+33

x coordinate of vertex is -b/2a in the form ax^2+bx+c=y
a=-1
b=-8
-(-8)/2(-1)=8/-2=-4
plug back in to get y value

y=-(-4^2)-8(-4)+33
y=-16+32+33
y=49

y value is 49
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Need help asap !!!!!
Romashka [77]

Answer:

The answer is x = 5.

Step-by-step explanation:

Given:

Δ ABC is an Isosceles triangle with AB = CA

   m∠ ABC = ( 6x + 4 )°

   m∠ BAC = 73°

   m∠ BCA = ( 8y - 7 )°

To Find:

x = ?

Solution:

Properties of an Isosceles Triangle.

  1. Base angles or two angles are equal.
  2. Any two sides are equal.

Here , Δ ABC is an Isosceles triangle with AB = CA

∴  m∠ BAC = m∠ BCA

73= 8y-7\\8y=73+7\\8y=80\\y=\frac{80}{10} \\y=10

∴      m∠ BCA = ( 8y - 7 )°

                       = 8 × 10 - 7

       m∠ BCA  = 73  Which is same as ∠ CAB

Property of a Triangle is Sum of the measures of the angle of a triangle is 180°.

\angle ACB + \angle CAB + \angle CBA = 180

Substituting the values we get,

73 + 73 + (6x+4) = 180\\6x+4=180-146\\6x=34-4\\6x=30\\x=\frac{30}{6} \\x=5\\

The answer is x = 5.

7 0
3 years ago
What is 0.8%of $5,700?
EastWind [94]

Answer: 0.8% of 5,700 = <u><em>45.6 </em></u>

Step-by-step explanation:

0.8% × 5,700 =

(0.8 ÷ 100) × 5,700 =

(0.8 × 5,700) ÷ 100 =

4,560 ÷ 100 =

45.6;

5 0
3 years ago
Read 2 more answers
5sin²α+3cos²α / 3sin²α-5cos²α = <br> if tgα=√2
fiasKO [112]
Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)

sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)

cos(α) = adjacent/hypotenuse
= 1/sqrt(3)

now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
8 0
3 years ago
The graph above is a transformation of the function x2 Write an equation for the function graphed above
lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2)   \ \ \ \  y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \  \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right  \\

We summarize (1) and (3):

2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.

Substitute b=-1 into (2):

9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\

From (5) subtract (4):

8a=4\ |:8\\a=0,5.\ \ \ \  \Rightarrow\\

Substitute a=0,5 into (4):

0,5+c=-1\\c=-1,5.

Hense:

y=0,5x²-x-1,5.

5 0
2 years ago
1. find the area 2.7m 12m<br><br>2. find the area 12 6ft<br><br>3. find the area 18ft 16ft
eduard

Answer:

Question 1 = 32.4ft Question 2 = 72ft Question 3  = 288ft

Step-by-step explanation:

Use multiplication.

7 0
3 years ago
Read 2 more answers
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