No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
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289 square root = 17
17*17=289
Say 17 was length and 17 was width. L*w=289
Also, all sides of the square are the same.
Answer:
{24, 18, 12, 6, 0} is the range of the above function
Step-by-step explanation:
solution:
let, x= -4
f(-2) = 12-3*(-2)
= 12+12
=24
let,x= -2
f(-2) = 12-3*(-2)
=12+6
18
let,x =0
f(0)= 12-3*0
=12-0
=12
let,x=2
f(2) = 12-3*2
=12-6
=6
let,x=4
f(4) = 12-3*4
=12-12
=0
When Deshawn installs a shelf bracket, the width of the shelf that will fit without overhang will be 3 inches.
<h3>How to calculate the width?</h3>
From the complete information, the other two sides have been given as 4 inches and 5 inches.
The Pythagoras theorem will be used in this case and it goes thus:
4² + Width² = 5²
Width² = 5² - 4²
Width² = 25 - 16
Width² = 9
Width = ✓9
Width = 3
In conclusion, the width is 3 inches.
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