Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
If you go from point (-1, -3) to point (4, 4), you can find the slope of the line using the slope formula.

. So our slope is 7/5. The line goes through the y axis at -3/2, so putting that together we get an equation for the line that is

, choice D from above.
Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
The square root of -17/16 is 0.257694102 i
<span>(2.0x10^4)(3.0x10^3)
= ( 2 x 3)( 10^4 x 10^3)
= 6 x 10^7
hope it helps</span>