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mart [117]
3 years ago
7

One angle measure in an acute triangle is 38°. What could the measure of one of the other angles be?

Mathematics
1 answer:
devlian [24]3 years ago
8 0
Sum of all the angles in a triangle = 180 degrees.
it's given is an acute angle so <90
degrees now one is 38 the sum of other two would be 142 now here 27 is not possible because then the third angle, would be 115 degrees.

hope this help
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Answer:

\left(\dfrac{2}{3},\dfrac{1}{5}\right)

Step-by-step explanation:

Given the system of two equations:

\left\{\begin{array}{l}\dfrac{1}{2}x-\dfrac{3}{4}y=\dfrac{11}{60}\\ \\\dfrac{2}{5}x+\dfrac{1}{6}y=\dfrac{3}{10}\end{array}\right.

Multiply the first equation and the second equation by 60 to get rid of fractions:

\left\{\begin{array}{l}30x-45y=11\\ \\24x+10y=18\end{array}\right.

Now multiply the first equation by 4 and the second equation by 5:

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Subtract them:

(120x-180y)-(120x+50y)=44-90\\ \\120x-180y-120x-50y=-46\\ \\-230y=-46\\ \\y=\dfrac{46}{230}=\dfrac{1}{5}

Substitute it into the first equation:

30x-45\cdot \dfrac{1}{5}=11\\ \\30x-9=11\\ \\30x=11+9\\ \\30x=20\\ \\x=\dfrac{2}{3}

The solution is \left(\dfrac{2}{3},\dfrac{1}{5}\right)

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<h3>Explanation:</h3>

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Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...

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For g(x) = sec(x)/x, consider g(-x).

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