Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 98.6
For the alternative hypothesis,
µ < 98.6
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 275
Degrees of freedom, df = n - 1 = 275 - 1 = 274
test statistic, t = (x - µ)/(s/√n)
Where
x = sample mean = 98.3
µ = population mean = 98.6
s = samples standard deviation = 1
t = (98.3 - 98.6)/(1/√275) = - 4.97
We would determine the p value using the t test calculator. It becomes
p < 0.00001
Since alpha, 0.01 > than the p value, then we would reject the null hypothesis. Therefore, the correct option is
B. Reject Upper H 0 since the P-value is less than the significance level.
