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pogonyaev
3 years ago
7

PHOTE HERE^solve for g need help asap

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0
Isolate the variable by dividing each side by factors that don't contain the variable.

g=-f+ \frac{2A}{H}
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Multiply or divide as indicated. <br><br> x 2 • x 5
WARRIOR [948]
Hi there!

{x}^{2}  \times  {x}^{5}  = x {}^{2 + 5}  =  {x}^{7}

We can also write is out entirely.
{x}^{2}  = x \times x
{x}^{5}  = x \times x \times x \times x \times x
{x}^{2}  \times  {x}^{5}  = \\  (x \times x ) \times (x \times x \times x \times x \times x) =  \\ x \times x \times x \times x \times x \times x \times x =  \\  {x}^{7}
6 0
3 years ago
getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0
3 years ago
689x+47x-89 dose anyone know how to solve this?
Korvikt [17]

Answer:

736x-89

Step-by-step explanation:

i think all you can do here is add the numbers that have an X in them so adding 689x+47x=736x and you leave the 89 so it becomes 736x-89

4 0
2 years ago
Read 2 more answers
Can someone solve these equations with the work, and explain how to do them? I'm completely lost and it's due tomorrow, plus ano
trapecia [35]
Yea what's the equations??
4 0
3 years ago
Need help with this art please
olga2289 [7]
This question should be answered with a ruler you have to measure them in mill meter and then put the numbers into the correct place for example
240 mm is with the hundreds section
And 57 is in the tens section
And more but don’t use the numbers i gave you they are only for examples
Hope it helps❤️
4 0
2 years ago
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