What is the differentiation of f(x) =2x^4/5?

1 answer:

6 0

$\bf f(x)=\cfrac{2x^4}{5}\implies f(x)=\cfrac{2}{5}x^4\implies \cfrac{df}{dx}=\cfrac{2}{5}\cdot 4x^3\implies \cfrac{df}{dx}=\cfrac{8x^3}{5}$

notice, the 2/5 is just a "scalar" value, so you can just get the derivative of the variable part and slap the scalar as its factor.

You might be interested in

Multiply the polynomials (x+4)(x^2-5x+3)

tatiyna

(4x2 – 4x – 7)(x + 3)
 = (4x2 – 4x – 7)(x) + (4x2 – 4x – 7)(3)
 = 4x2(x) – 4x(x) – 7(x) + 4x2(3) – 4x(3) – 7(3)
 = 4x3 – 4x2 – 7x + 12x2 – 12x – 21
 = 4x3 – 4x2 + 12x2 – 7x – 12x – 21
 = 4x3 + 8x2 – 19x – 21

6 0

3 years ago

Read 2 more answers

Find the measure of an angle such that the difference between the measures of its supplement and four times its complement is 30

Katarina [22]

Answer:

70 degrees

Step-by-step explanation:

x = angle

180 - x = it's supplement

90 - x = it's compliment

(180 - x) - 4(90 - x) = 30

180 - x - 360 + 4x = 30

reducing

3x = 210

x = 70

7 0

3 years ago

What percent of 9.2 m is 2.5

Nadusha1986 [10]

To solve this, you just simply divide to get a decimal and then convert to a percentage.

2.5 divided by 9.2 is equal to approximately 0.2717.

You then multiply that by one hundred to get a percentage. So the final answer is approximately 27.17%.

7 0

3 years ago

Read 2 more answers

Samuel used 1/5 of an ounce of butter to make 1/15 of a pound of jelly. How many ounces of butter are needed to make a pound of

vredina [299]

Set up ratio problem

.2 oz butter / (1/15) lb jelly = x / 1 lb jelly

Then cross multiply the stuff opposite each other in the fractions... set it up as a multiplication problem

.2 × 1 = (1/15) × x

.2 = (1/15)x

Multiply both sides of equation by 15 to clear out the (1/15) fraction and get x

x = 3

8 0

4 years ago

Please help me :(

damaskus [11]

You could use sine to find it
sin45 = 8/m
m = 8/sin45

3 0

3 years ago