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3 years ago

What is (37-26) squared - 6 divided by -32 divided by 2 squared - (4 squared - 13) Plz help!

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

3 0

If this is your equation, then:

(37-26)² - (6÷-32÷2²) - (4²-13)

(11²) - (-3/64) - (3)

(121) - (-3/64) - (3)

7555/64

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If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0

3 years ago

13. Solve 2/3 + 5/6 and put answer in simplest form. O A. 11/2 B. c. 76 D.776

Tamiku [17]

Answer:

3/2 or 1 + 1/2

i havent done fractions in a long time but this is what i got from memory

you turn the 2/3 into 4/6 so they can easily be added together to get 9/6 which can be simplified to 3/2 or in proper form 1 + 1/2

8 0

3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

Please Help Find the correct one and please show your work!!!

LekaFEV [45]

Answer: c because it got 4 and going down equally i guess

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the sine value of 2 pi over 3? negative 1 over 2 1 over 2 negative square root 3 over 2 square root 3 over 2

MatroZZZ [7]

Answer:

$\large\boxed{\sin\dfrac{2\pi}{3}=\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

$\sin\dfrac{2\pi}{3}=\sin\bigg(\pi-\dfrac{\pi}{3}\bigg)\\\\\text{use}\ \sin(x-y)=\sin x\cos y-\sin y\cos x\\\\=\sin\pi\cos\dfrac{\pi}{3}-\sin\dfrac{\pi}{3}\cos\pi\\\\\text{use the table from the attachment}\\\\\sin\pi=0\\\\\cos\dfrac{\pi}{3}=\dfrac{1}{2}\\\\\sin\dfrac{\pi}{3}=\dfrac{\sqrt3}{2}\\\\\cod\pi=-1\\\\\text{subtitute:}\\\\=(0)\left(\dfrac{1}{2}\right)-\left(\dfrac{\sqrt3}{2}\right)(-1)=\dfrac{\sqrt3}{2}$

7 0

3 years ago