Answer: always
Step-by-step explanation:
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
9 < √91 < 10
Step-by-step explanation:
just square everything
Answer:
within-groups
Step-by-step explanation:
According to my research on the scientific method, I can say that based on the information provided within the question the independent variable is being manipulated within groups, because she is not using a pretest and her design is within-groups. This is because she is using the posttest-only control group design which is a research design where at least two groups, one of which does not receive a treatment or intervention, and data is collected on the outcome measure after the treatment or intervention.
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Line all the numbers in a column and compared where the numbers are not the same numbers