Total amount=9 chicken.($5/chicken)+15 burguer meals.(6$/burquer meal)=
=$45+$90=$135.
Percent (chicken meals)=($45.100%) / $135=33,33%.
Solution: 33,33%.
If I’m not wrong I think it’s x+1
Answer:
Anton played a total of 39 games.
Step-by-step explanation:
If you want to calculate the amount of games played, you must first subtract the membership fee of 895 to get 1170. As you are charged $30 for each game, you must divide by thirty.
If you are fond of graphing, know this equation can also be expressed in slope-intercept form (y = mx + b) as y = 30x + 895, with x being the number of games played and the y-intercept (895) being your initial cost.
The expected value is $0.11.
The probability that the player will make the next free throw is 233/402. The probability that the next 3 are made will be (233/402)^3. To find the expected value of this, we multiply by the winnings we would have in this case, 166. So far we have:
((233/402)^3)(166)
The probability that the next 3 are not made is 1-((233/402)^3). Multiply this by the loss, -40, to get its expected value. This gets us to:
((233/402)^3)(166)-(1-((233/402)^3)).
This comes out to $0.11.
