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Evgesh-ka [11]
3 years ago
5

45 divided by 2531 HELP IDK HOW TO DO THIS.

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0
 0.017779534 because you just divide it
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Georgia [21]
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Answer:
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4 0
3 years ago
There were 4 crates of 18 peaches each all the peaches were put into 3 boxes equally how many peaches were there in each box
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6 peaches were there in each box

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5 0
3 years ago
Factorise <br> P(x)= (x+3)(12x^2-3)+(2x-1)(x^2-9)<br> And<br> Q(x)= 4x^4-x^2
Archy [21]

Answer:

a2 answers to exercises

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8 0
3 years ago
Read 2 more answers
Solve the formula for the indicated variable  c=yt+y,for t (the solution is t=___)
Vlad1618 [11]
C=yt+y. Divide both sides by y and u get c/y=t+1 subtract 1. The ANSWER IS c/y-1=t
7 0
3 years ago
Will rate7 you brainliest
Vilka [71]

Answer:

\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)

\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)

\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)

\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)

Now, let's compute the product.

\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}

So the correct answer is the first one.

Thank you.

7 0
4 years ago
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