transitional cells differ from epithelial cells in that they A) can stretch more B) lack tight junctions between the cells C) ha
2 answers:
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Answer:
6 offsprings with white fur
Explanation:
The gene involved here codes for fur colour in mice where the allele for brown fur (B) is dominant over the allele for white fur (b) i.e. the B allele will mask the expression of b allele in an heterozygous state (Bb).
Since allele B is dominant, in an heterozygous state (Bb), the mice will be brown-furred. Hence in a cross between two Bb parents, a phenotypic ratio of 1:2:1 will be produced where;
1 is BB (homozygous brown fur), 2 is Bb (heterozygotic brown fur) and 1 is bb (homozygous white fur).
Hence, 1/4 × 100= 25% offsprings will be white furred. If 24 mice result, 25/100 × 24 = 6 offsprings will be white.
Answer:
0
Explanation:
This question involves two genes; A and B. According to the question, two parents are crossed as follows: AABB × Aabb. The parents will produce the following gametes:
AABB- AB, AB, AB, AB
Aabb - Ab, Ab, ab, ab
Using these gametes in a punnet square (see attached image), the offsprings in the following proportion will be produced:
AABb = 4/16 = 1/4
AaBb = 4/16 = 1/4
Therefore, none (0) of the offsprings will resemble the phenotype of the second parent (Aabb).
