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DaniilM [7]
4 years ago
8

thirty percent of those in attendance have never seen a lacrosse match before. how many of the 400 in attendance were watching t

heir first game of lacrosse? how many have previously seen a lacrosse game
Mathematics
1 answer:
Maurinko [17]4 years ago
7 0

Answer:

sorry can u give me a like im tring to get points it my first day

Step-by-step explanation:

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Raise 5 to the 3rd power, then find the quotient of the result and s
Art [367]

Answer:

125/s

Step-by-step explanation:

5^3 = 5 x 5 x 5 = 25 x 5 = 125

Find the quotient of the result and s

125 ÷ s

= 125/s

Hope this helps :)

8 0
3 years ago
Two sides of a triangle have lengths 9 m and 13 m. The angle between them is increasing at a rate of 0.02radians /min. How fast
Olin [163]

Answer:0.175 m/s

Step-by-step explanation:

Given

Two sides of length 9 and 13 m

angle between them is increasing at an angle of 0.02 rad/min

rate of increasing of third at \theta =\frac{\pi }{3}

let a=9

b=13

c=unknown side

Now using cos rule of triangle

cos\theta =\frac{a^2+b^2-c^2}{2ab}

cos\theta =\frac{a^2+b^2}{2ab}-\frac{c^2}{2ab}

Differentiating both sides we get

-\sin \theta \times \frac{\mathrm{d} \theta }{\mathrm{d} t}=0-2\frac{c}{2ab}\times \frac{\mathrm{d} c}{\mathrm{d} t}

at \theta =\frac{\pi }{3}

c=11.53 m

substituting values we get

\frac{\sqrt{3}}{2}\times 0.02=\frac{11.53}{9\times 13}\times \frac{\mathrm{d} c}{\mathrm{d} t}

\frac{\mathrm{d} c}{\mathrm{d} t}=0.175 m/s

8 0
3 years ago
A Web site goes viral. The number of users triples each day. What is the constant percentage increase each day?
aksik [14]

We know that the number of users triple each day

Let number of users on day 1 be x

⇒ Users on day 2 = 3 * (x) = 3x

and Users on day 3 = 3 * (3x) = 9x

And so on...

% Increase in users from day 1 to day 2 = \frac{\text{Users on Day 2 - Users on Day 1}}{\text{Users on Day 1}} * 100

⇒ % Increase in users from day 1 to day 2 = \frac{3x-x}{x} * 100

⇒ % Increase in users from day 1 to day 2 = \frac{2x}{x} * 100

⇒ % Increase in users from day 1 to day 2 = 200%

Similarly,

% Increase in users from day 2 to day 3 = \frac{\text{Users on Day 3 - Users on Day 2}}{\text{Users on Day 2}} * 100

⇒ % Increase in users from day 2 to day 3 = \frac{9x-3x}{3x} * 100

⇒ % Increase in users from day 2 to day 3 = \frac{6x}{3x} * 100

⇒ % Increase in users from day 2 to day 3 = 200%

Hence, we can see that the percentage increase each day is 200%

3 0
4 years ago
(50 POINTS) Express each sum using summation notation.
vesna_86 [32]

14: a

1

=

39

/2                              0.25               313%        16%

15:     54

4 0
3 years ago
Mr. Brooks has $14.20 in his checking account, he uses
Lesechka [4]

Answer:

-$22.80.

Step-by-step explanation:

The 4 meals cost 4.25 * 4 = $17 which gives him a new balance of  

14.20 - 17 -20

= -$22.80.

5 0
3 years ago
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