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2 years ago

In need help please

Mathematics

1 answer:

pantera1 [17]2 years ago

5 0

Answer:

->a is 2

->b is one eight

Step-by-step explanation:

one fourth dividen in two becomes one eight.

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Does 9, 10 and 15 equal a right triangle

vagabundo [1.1K]

Answer:

By virtue of The pythagorean theorem,in a right triangle squares of the similar two sides equal the square of The largest side.Only 9,12 and 15 fit this rule.

Step-by-step explanation:

Hope it help you If you have any questions can ask in the comments

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2 years ago

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Hi! I attached the question

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Yes, By SAS

Step-by-step explanation:

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What is the answer to -3.4 - 1.6?

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Answer:

-5

Step-by-step explanation:

-3.4 - 1.6 = -5

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2 years ago

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3 years ago

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What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

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2 years ago