Question

Noah has $50. He wants to buy a cell phone case for $20 and some accessories. Each accessory costs $8. How many accessories (x) can Noah buy if he wants to have more than $8 left after he buys everything? Use the equation editor to enter the missing part of the inequality that answers the question. The inequality answer must be a whole number.

Answer 1

Answer:

Noah can buy 2 accessories.

Step-by-step explanation:

Given:

Money Noah has = $50

Cost of Cell phone case = $20

Cost of each accessory =$8

Amount he wants to be left = $8

So Total Amount he he wants to spend on accessories and Cell phone case will be equal to Money Noah has minus Amount he wants to be left.

framing in equation form we get;

Total Amount he he wants to spend on accessories and Cell phone case = $\ 50-\ 8 =\ 42$

No we need to find the number of accessories Noah can buy.

Let the number of accessories be 'x'.

Now we can say that;

Cost of Cell phone case plus Cost of each accessory multiplied by number of accessories should be less than or equal to Total Amount he he wants to spend on accessories and Cell phone case.

framing in equation form we get;

$20+8x\leq 42$

Subtracting both side by 20 we get using Subtraction property of Inequality.

$20+8x-20\leq 42-20\\\\8x\leq 22$

Now Dividing both side by 8 using Division property of Inequality we get;

$\frac{8x}{8}\leq \frac{22}{8}\\\\x\leq 2.75$

Now rounding to whole number we get ;

$x\leq 2$

Hence Noah can buy 2 accessories.