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Anna11 [10]
3 years ago
6

How to find the values of x and y.

Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0
Use the trigonometric function.

\sin30^o=\dfrac{x}{20}\\\\\sin30^o=\dfrac{1}{2}\\\\\dfrac{x}{20}=\dfrac{1}{2}\ \ \ |\cdot20\\\\x=10

\sin60^o=\dfrac{y}{20}\\\\\sin60^o=\dfrac{\sqrt3}{2}\\\\\dfrac{y}{20}=\dfrac{\sqrt3}{2}\ \ \ \ |\cdot20\\\\y=10\sqrt3
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Fittoniya [83]

Answer:

Step-by-step explanation

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3 years ago
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Present Value Hoew much shuold be deposited in an account paying 7.2% interest compounded monthly in order to have a balance of
jonny [76]

Answer:$6451.6 should be deposited.

Step-by-step explanation:

The principal was compounded monthly. This means that it was compounded 12 times in a year. So

n = 12

The rate at which the principal was compounded is 7.2%. So

r = 7.2/100 = 0.072

It was compounded for 3 years. So

t = 3

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. A is given as $8000 Therefore,

8000 = P (1+0.072/12)^12×3

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6 0
3 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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topjm [15]

You have to find the angle for it try it!!!!!!!!!!

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3 years ago
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