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lana66690 [7]
3 years ago
8

Find the equation of the circle that has a diameter with endpoints located at (-3,6) and (9,6)

Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

The equation of the circle is:

(x-3)^2+(y-6)^2=36

Step-by-step explanation:

Notice that the points at the two extremes of the diameter they give you are both located along the line y=6, and are separated by each other the distance given by: 9-(-3) = 12. So the diameter of the circle is 12 units, and then its radius is half of that: 6 units. (r = 6).

Now the center of the circle must be located also on the line y=6, and its x position must be that of the equidistant point to the two extremes. that is: x center = 9-6 = 3

Then the center of the circle is at the point (3,6) in the plane.and its radius is r=6. With this info, we can use the standard equation for a circle of radius r and center (x_0,y_0):

(x-x_0)^2+(y-y_0)^2=r^2\\(x-3)^2+(y-6)^2=6^2\\(x-3)^2+(y-6)^2=36

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(10 1/4 - 5 5/8) - 1 3/8
Allisa [31]
3 1/4

should be it!

Hope that helps!
5 0
3 years ago
What is the Compound Inequality that is true for the missing side length? 3cm, 4cm, Xcm
Brrunno [24]

Answer:

x< 3+4\: and\\\left | 3-4 \right |

Step-by-step explanation:

1. Well, when it comes to triangles. Mainly Pythagorean Triple, right triangles whose sides are 3,4,5 or  5,11,12

2. Keeping in mind this a Pythagorean Triple, then x=5

3. Then we can write it as Compound Inequality by combining the Statements for an Inequality of Triangle:

We can write it as

5

Or we can do:

4

and:

3

4. Writing in terms of x:

x

3 0
3 years ago
Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
Alicia, Quentin, and Rosalyn are siblings. Alicia is the oldest sibling. Quentin is four years younger than Alicia. Rosalyn is t
tatiyna

Answer:

Alicia is 18years

Quentin is 14years

Rosalyn is 16years

Step-by-step explanation:

Let the age of Alicia be x

Let the age of Quentin be y

Let the age of Rosalyn be z

If the sum of the siblings’ ages, in years, is 48 then;

x+y+z = 48.... 1

If Rosalyn is two years older than Quentin then;

z =y+2 ..... 2

Also if Quentin is four years younger than Alicia then;

y = x-4 ... 3

From 3:

x = y+4 ... 4

Substitute 2 and 4 into 1 to have:

y+4+y+y+2 = 48

3y + 6= 48

3y = 48-6

3y= 42

y = 14

Since x= y+4

x = 14+4

x = 18

Since z = y+2

z = 14+2

z = 16year

This means that;

Alicia is 18years

Quentin is 14years

Rosalyn is 16years

6 0
3 years ago
Solve for X when the surface area is 298ft^2
jok3333 [9.3K]

Step-by-step explanation:

Total surface area of cuboid= 2(lb+bh+hl)

= 298ft²=2(28+4x+7x)

= 149=28+11x

= 121=11x

= 11=x

6 0
2 years ago
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