Answer:
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Step-by-step explanation:
Answer:
Probablity of getting six in at most three roll= 0.199.
Step-by-step explanation:
Given: Dice rolled at most 3 times untill a 6 occurs.
First, finding the probablity of getting 6 in a dice if rolled once.
Probablity= 
We know, dice have six side, therefore, total number of event will be 6.
∴ Probablity of getting six in one roll= 
As given, Dice is rolled at most 3 times.
Now, finding the probablity of getting 6 in a dice if rolled 3 times.
∴ Probablity of getting six in three roll= 
⇒ Probablity of getting six in three roll= 
Taking LCD 216
⇒Probablity of getting six in three roll= 
⇒Probablity of getting six in three roll= 
∴Probablity of getting six in three roll=0.199
Answer: 0.75 (choice B)
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Explanation:
One way to set up the equation is to think of it like this
vertical/horizontal = vertical/horizontal
So we could say
(3.5)/(28) = x/6
Cross multiply and solve for x
3.5*6 = 28*x
21 = 28x
x = 21/28
x = (3*7)/(4*7)
x = 3/4 in fraction form
x = 0.75 in decimal form
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Another possible set up equation is
28/6 = (3.5)/x
in this case I divided the horizontal sides together (28 and 6) and the vertical sides divide to form their own separate fraction as well.
Solving that equation should lead you to x = 3/4 = 0.75
Other equations are possible.
36/72=0.5
0.5*100=50
Therefore 36 is 72% of 50
Hope this helps :)
A point serves as the midpoint<span> of a segment if it lies on the segment and it divides the segment into two congruent segments. Other notes to. So the coordinates of B and D are </span>4<span> and 10, respectively,. and the. Because AC = </span>9<span> and CE = </span>9<span> so C divides into two. 10 + 3 = </span>13<span>, so the coordinate </span>for<span> the other endpoint is </span>13<span>.
Hope this helped
heres a pug for good luck</span>