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erastova [34]
3 years ago
9

Which polygons have no right angles?

Mathematics
2 answers:
andreev551 [17]3 years ago
7 0
Octogons, and hexagons don’t have right angles
asambeis [7]3 years ago
4 0

Answer:

Rhombus,and pentagon

Step-by-step explanation:

a rhombus has only obtuse or acute angles same with the pentagon.

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Find the square root. 7.29 ​
Serjik [45]

Answer:

2.7

Step-by-step explanation:

√7.29=2.7

6 0
3 years ago
 A submarine is at an elevation -100 feet( 100 feet below sea level) let’s compare the elevation of these for people to that of
Svetradugi [14.3K]
<h3>A submarine is at an elevation of -100 feet (100 feet below sea level). Let’s compare the elevations of these four people to that of the submarine:</h3>
  • Clare’s elevation is greater than the elevation of the submarine. Clare is farther from sea level than the submarine.
  • Andre’s elevation is less than the elevation of the submarine. Andre is farther away from sea level than the submarine.
  • Han’s elevation is greater than the elevation of the submarine. Han is closer to sea level than is the submarine.
  • Lin’s elevation is the same distance away from sea level as the submarine’s.
8 0
2 years ago
A shed has dimensions of 12m in length and 5 m in width. Both the length and width are increased by the same amount in order to
mestny [16]

The amount by which the length and width of a shed can be increased to

more than double the area, depends on the initial dimensions.

  • The amount that can be added to both the length and the width to increase the floor area by more than double the original area is more than <u>3 meters</u>.

Reasons:

The given parameters of the shed are;

The length of the shed = 12 m

Width of the shed = 5 m

The amount by which the length and the width are increased = The same amount

The new area after the increase in the length and width of the shed = More than double the initial area

Required:

The amount of increase in the length.

Solution:

Let the amount by which the length and width are increased = x

We have;

Initial area of the shed = 12 m × 5 m = 60 m²

The new area = (12 + x) × (5 + x) > 2 × 60

By multiplication, we get;

(12 + x) × (5 + x) = x² + 17·x + 60 > 2 × 60 = 120

x² + 17·x + 60 - 120 > 120 - 120 = 0

x² + 17·x - 60 > 0

By factorization, we get;

(x + 20)·(x - 3) > 0

x > -20, or x > 3

The increase (positive) amount of the solution is x > 3

Therefore, <u>the amount by which both the length and the width can be increased to more than double the area is x > 3 meters</u>

Learn more about the area of a rectangle here:

brainly.com/question/16410706

7 0
2 years ago
Natalie just invited 100 guests to a party in her small house. The base of her house is a rectangle with dimensions 8m by 16m. I
Alex787 [66]

Answer:

6 units by 12 units

Step-by-step explanation:

Since the measurements in meters are multiples of 4, it makes this problem a little easier.

First you divide 8 by 4 to get 2

Then divide 16 by 4 to get 4

After that you're going to multiply 3 units by both quotients separately.

So you multiply 3 by 2 to get 6

Then you multiply 3 by 4 to get 12

So then you end up with a 6 unit by 12 unit drawing.

It's funny because I was actually looking for the answer to this problem. Sorry I was a little late

5 0
3 years ago
What is the law of sines
galina1969 [7]
Sine is also known as Opposite over hypotenuse. 
5 0
3 years ago
Read 2 more answers
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