Answer:
for 15 crayons box she can spend
Step-by-step explanation:
The computation of the number of crayons for which she can spend is shown below:
Given that
She can spend $30
And, the cost is 2 per box
So, for the number of crayons for which she can spend is
= $30 ÷ 2
= 15 crayons box
Hence, for 15 crayons box she can spend
The same would be relevant
Answer:

Step-by-step explanation:
If ΔABC ~ ΔDEF
Then their sides must be proportional such that:
=> 
Cross Multiplying
=> x * 6 = 8*3
=> 6x = 24
Dividing both sides by 6
=> x = 4
Answer:
Step-by-step explanation:
Answer:
if there is an overabundance of predators then the predators might get competitive between themselves since most of the prey would be gone.
Step-by-step explanation:
<span>b. true. the spread of a normal distribution is completely determined by its standard deviation.
A normal distribution is defined by 2 values, its mean and it's standard distribution. The standard distribution determines what the shape of the curve looks like. A small distribution causes the curve to be tall and skinny. A large distribution causes the curve to be short and fat. The overall shape is entirely determine by the standard deviation. The exact location of the peak is determined by the mean. So let's look at the options and see why they're right or wrong.
a. false. the spread of a normal distribution is completely determined by its mean.
* This is exactly wrong. The mean determines where the peak is, the shape is determined by the standard distribution.
b. true. the spread of a normal distribution is completely determined by its standard deviation.
* This is absolutely correct.
c. true. the spread of a normal distribution is completely determined by its median.
* Once again, it's swapping the meaning between mean and standard distribution.
d. false. the spread of a normal distribution is determined by both its mean and standard deviation.
* This is a bit of weasel wording here. But remember, the SHAPE is determined by the standard distribution while the location of the peak is determined by the mean.</span>