
Let
, so that
:

Now the ODE is separable, and we have

Integrating both sides gives

For the integral on the left, rewrite the integrand as

Then

and so


Given that
, we find

so that the particular solution to this IVP is

Answer:

Step-by-step explanation:

(a) Rename h(x) as y

(b) Solve for x :

(d) Switch x and y

(e) Rename y as the inverse function

The graphs of inverse functions are reflections of each other across the line y = x.
In the diagram, the graph of h⁻¹(x) is the reflection of h(x) about the line y = x.
Interior angles of a square always sum to 360°. A reflection in the x-axis would not change this.
Answer:
both are the same
Step-by-step explanation:
2.0 = 2
hope this helps ^-^