6 phone numbers are possible for one area code if the first four numbers are 202-1
<u>Solution:</u>
Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order
We have to find how many phone numbers are possible for one area code.
The number of way “n” objects can be arranged is given as n!
Then, we have three places which changes, so we can change these 3 places in 3! ways

Hence 3! is found as follows:

So, we have 6 phone numbers possible for one area code.
Answer:
a+b = 4
Step-by-step explanation:
3(a + b)^2 = 81
(a + b)^2 = 27
a + b = sq rt 27
a + b =
· 
a + b = 3
I believe it's A, C and D.
The answer is 13 because you would plug in 3(3) which is 9 then you multiply (9)(2) which is 18 they you subtract 18-5 which equals 13