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3 years ago

13

A toy company spends $20 for every doll it makes. Promotion of the dolls costs $400 and the company sells each doll for $30. How

many dolls must the company sell to make a profit?
What inequality represents this problem?

Question 3 options:

20d+400<30d

20d−400>30d

20d−30d>400

20d+30d>400

1 answer:

Romashka-Z-Leto [24]3 years ago

4 0

Answer:

$20d+400< 30d$

Step-by-step explanation:

we know that

The profit is equal to the number of dolls multiplied by the selling price minus the number of dolls multiplied by the cost of each doll minus the cost of the promotion of the dolls

To make a profit, the number of dolls multiplied by the selling price minus the number of dolls multiplied by the cost of each doll must be greater than the cost of the promotion of the dolls

Let

d -----> the number of dolls

The linear inequality that represent this problem is

$30d-20d > 400$

Adds 20d both sides

$30d > 20d+400$

Rewrite

$20d+400< 30d$

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