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liq [111]
2 years ago
5

one angle has a measure that is less than 15 than two times a number. a second angle is three times the number. the angles are c

omplementary. find the measures of each angle​
Mathematics
1 answer:
adell [148]2 years ago
4 0

Answer:

27 degrees and 63 degrees

Step-by-step explanation:

Let n be the number.

Angle 1: 2n-15

Angle 2: 3n

If the angles are complementary they add up to 90.

Therefore we can write an equation.

2n-15+3n=90

Combine like terms

5n-15=90

Add 15 to both sides

5n=105

n=21

Now we plug 21 in for n and solve for the angles

Angle 1 = 2(21)-15

Angle 1 = 42-15

Angle 1 = 27

Angle 2 = 3(21)

Angle 2 = 63

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Endpoint 1: (-1,2)<br> Midpoint: (9,-6)<br> Endpoint 2=
Vlad [161]

Answer:

(19 , -14)

Step-by-step explanation:

Find the distance in between each x & y for a coordinate.

Let: (x₁ , y₁) = (-1 , 2)

Let: (x₂ , y₂) = (9 , -6)

From x₁ ⇒ x₂: 9 - (-1) = 10

From y₁ ⇒ y₂: -6 - 2 = -8 = 8*

*Remember that distance cannot be negative, but for the sake of this question, we will leave it as -8.

The distance between the x points are in intervals of 10. The distance between the y points are in intervals of 8. Add 10 & subtract 8 to their respective numbers to get endpoint 2:

(9 (+ 10) , -6 (- 8)) = (19 , -14)

Endpoint 2 = (19 , -14)

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7 0
3 years ago
Help with Pre Calculus
marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. x(2x^2-x-15). So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\. So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}

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2 years ago
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Step-by-step explanation:

given,radius =5 m

height =8 m

now, v=pi×r^2×h

=(3.14×5^2×8)m^3

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