Answer:
Accelerating to top speed, deaccelerating to finish line.
Step-by-step explanation:
If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:
This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.
Answer:
The two linear equation
x + y = 19.... Equation 1
0.55x + 0.75y = 12.65... Equation 2
Nedra purchased
9 Apples and 11 Oranges
Step-by-step explanation:
Nedra purchased apples and oranges at the grocery store. which two linear equations can be used to find the number of apples and oranges?
Let the number of apples be represented by x
The number of oranges by represented by y.
Hence,
Apples are $0.55 each and oranges are $0.75 each. If she spent a total of $12.65 for 19 pieces of fruit,
Hence:
x + y = 19..... Equation 1
x = 19 - y
$0.55 × x + $0.75 × y = $12.65
0.55x + 0.75y = 12.65.....Equation 2
Hence: we substitute 19 - y for x in Equation 2
0.55(19 - y) + 0.75y = 12.65
10.45 - 0.55y + 0.75y = 12.65
-0.55y+ 0.75y = 12.65 - 10.45
0.20y = 2.2
y = 2.2/0.20
y = 11 oranges
x = 19 - y
x = 19 - 11
x = 8 Apples
Acceleration is the change in velocity with respect to the time. The acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.
<h3>
Given information-</h3>
Segment A runs from 0 seconds 0 meters per second to 1 seconds 30 meters per second.
Segment B runs to 3 seconds 30 meters per second.
Segment C runs to 6 seconds 10 meters per second.
Segment D runs to 7 seconds 10 meters per second.
Segment E runs to 10 seconds 20 meters per second.
<h3>Acceleration</h3>
Acceleration is the change in velocity with respect to the time. Acceleration of a vector quantity which means it has both magnitude and the direction. It can be given as,

Here
denotes the time and
denotes the velocity of the body.
Acceleration at segment C,


Thus the acceleration of the car at segment C is -30 meter per second squared. Hence the option B is the correct option.
Learn more about the acceleration here;
brainly.com/question/2437624
Answer:
I'm pretty sure is the $0.40