Answer:
4.0 meters, ∠C = 39°, ∠A = 51°
Step-by-step explanation:
Firstly, our diagram shows us that the given triangle is actually a right triangle. So we can use the <em>Pythagorean Theorem</em> to solve for the height of the chain:






Now, we can use the <em>Law of Cosines</em> to figure out one of the acute angles:





∠C = 39°
And since we know that all angles in a triangle add up to 180°:
∠A + ∠B + ∠C = 180
∠A + 90 + 39 = 180
∠A = 180 - 90 - 39
∠A = 51°
However, you should always review any answers on the Internet and make sure they are correct! Check my work to see if I made any mistakes!
Answer:
{2, 4, 6}
Step-by-step explanation:
the domain is the interval or set of valid x (input) values.
the range is the interval or set of valid y (result) values.
all we need to do is use the given x values in the functional definition and collect the result values. that is the range.
x = -1
y = 2×-1 + 4 = 2
x = 0
y = 2×0 + 4 = 4
x = 1
y = 2×1 + 4 = 6
Answer:
x = 14
Step-by-step explanation:
First put it into slope intercept form
20 = 2x - 8
Move the variable to the left hand side and change its symbol
-2x + 20 = -8
Move the constant to the right hand side and change its symbol
-2x = -8 - 20
Calculate the difference
-2x = -28
Divide both sides of the equation by -2
x = 14
Solution
X = 14
Answer:
![\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%269%5C%5C5%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%260%5C%5C-8%264%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%269%5C%5C-3%262%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
To add matrices, we add the corresponding components.
The given matrices is
![\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%269%5C%5C5%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%260%5C%5C-8%264%5Cend%7Barray%7D%5Cright%5D)
We add the corresponding components to get;
![\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}3+6&9+0\\5+-8&-2+4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%269%5C%5C5%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%260%5C%5C-8%264%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%2B6%269%2B0%5C%5C5%2B-8%26-2%2B4%5Cend%7Barray%7D%5Cright%5D)
We simplify to get:
![\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%269%5C%5C5%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%260%5C%5C-8%264%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%269%5C%5C-3%262%5Cend%7Barray%7D%5Cright%5D)
Answer:
Salena's got to the library first
Step-by-step explanation:
12½ miles = 25/2 miles
2½ miles = 5/2 miles
5¾ miles = 23/4 miles
114 miles = 114 miles
Salena's time of arrival =
if 5/2 miles : 5 minutes
then 25/2 miles : ?
25/2 ÷ 5/2. × 5
25/2 × 2/5 × 5
25 minutes
Justin 's time of arrival=
if 23/4 miles : 12 minutes
25/2 miles : ?
25/2 ÷ 23/4 ×12
25/2 × 4/23 ×12
26 minutes approximately
Brandon 's time of arrival=
if 114 miles : 258 minutes
25/2 miles : ?
25/2 ÷114 ×258
25/2 × 1/114×258
25 × 1/57 × 258
113 minutes approximately