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Pavlova-9 [17]
3 years ago
8

How many thirtieths in 400 sq ft

Mathematics
2 answers:
ozzi3 years ago
7 0
Thirties in 400
ok well we could find out by dividing 400 by 30.
400 / 30 = 13.333333
We Can Round That To 13
Theres Your Answer (13)
never [62]3 years ago
6 0
Are you asking how many thirtieths there are in 400 ?

Well there are 30 of them in each ' 1 ', so in 400,
there are

                 (400) x (30)  =  12,000 thirtieths .
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wel

Answer:

3. D

4. C

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Step-by-step explanation:

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2 years ago
Q. A customer wants to re-carpet a living room andhallway. You charge $5.99 per square yard toremove old carpet and $4.50 per sq
Tanzania [10]

Living Room Area = 17.5 x 20 = 350 sq ft

Hall Area = 4 x 12 = 48 sq. ft.

Total area of carpeting: 340 + 48 = 398 sq. ft.

We need to convert total area in sq ft to sq yd. The conversion ratio is

1 sq ft = 0.11 sq yd

So, 398 sq ft would be:

398 * 0.11 = 44.22 sq yd.

Carpet removing rate is 5.99 per sq yd.

Removing rate would be:

44.22 * 5.99 = $264.88

Assuming you gotta install both carpet and pad,

Carpet + pad = 16.99 + 3 = 19.99 per sq yd.

You gotta buy for 44.22 sq yd.

So, it will cost (carpet):

44.22 * 19.99 = $883.96

Installing rate 4.50 per sq yrd, so to carpet 44.22 sq yd, would need:

4.50*44.22 = $198.99

Assuming carpet is provided by installation guys, total charge:

<h2>264.88 + 883.96 + 198.99 = $1,347.83</h2>
4 0
1 year ago
On July 3rd, a family left for vacation. They drove 431.2 miles on the first day, then they drove an average of 826.4 miles each
Alexxx [7]
431.2+826.4d=2910.4
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6 0
2 years ago
The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: T
jasenka [17]

Answer:

For the code we have 3 selections.

The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}

So we have 5 options.

The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)

So here we have 27 - 5 = 22 options

The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.

Here we have 22 - 1 = 21 options.

The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:

C = 5*22*21 = 2310.

There are 2310 different possible codes

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3 years ago
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