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Pavlova-9 [17]
4 years ago
8

How many thirtieths in 400 sq ft

Mathematics
2 answers:
ozzi4 years ago
7 0
Thirties in 400
ok well we could find out by dividing 400 by 30.
400 / 30 = 13.333333
We Can Round That To 13
Theres Your Answer (13)
never [62]4 years ago
6 0
Are you asking how many thirtieths there are in 400 ?

Well there are 30 of them in each ' 1 ', so in 400,
there are

                 (400) x (30)  =  12,000 thirtieths .
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8 0
4 years ago
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damaskus [11]

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hope this helps :)

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3 years ago
A square field had 3 m added to its length ad 2 m added to its width. The field then had an area of 90 m squared. Find the lengt
pogonyaev

Answer:

The length of a side of the original field  = 7 m.

Step-by-step explanation:

Here, the initial field is in form of a square.

Let us assume the side of the original square field = k meters

Now, the new length of the field = ( k + 3)  m

The new width of the field = ( k + 2) m

So, the new field is now a rectangle with area  = 90 sq. m

AREA OF A RECTANGLE  = LENGTH x WIDTH

Here, the area of the new field  =  New length x new width

                                                      =   ( k + 3) x ( k + 2)

90   =   ( k + 3) \times ( k + 2)\\\implies k^2 + 2k + 3k + 6 = 90\\or, k^2 + 5 k - 84 = 0\\\implies k^2 + 12k - 7k -84 = 0\\or, k (k+12) -7(k+12) = 0\\\implies (k+12)(k-7) = 0

⇒ either (k +12) = 0 ⇒  k = -12

or, ( k-7) = 0 ⇒  k = 7

But, here k = SIDE OF A FIELD, and it CANNOT be negative.

⇒  k = 7

Hence, the length of a side of the original field  = 7 m.

4 0
3 years ago
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Oduvanchick [21]

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⇒   (f⁻¹)'(b) = 1/f'(a)

Let b = 10. Then pick the function f(x) such that f(a) = 10 and f'(a) = -8 for some number a.

7 0
2 years ago
A few years ago, the Colorado Rockies played 160 games and won 64. For every 2 games they won, how many games did they lose?
yaroslaw [1]

Answer:

B

Step-by-step explanation:

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