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professor190 [17]
3 years ago
10

Which of the following is the solution to the following systems of inequalities? (picture included)

Mathematics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

  C.  (see the attachment)

Step-by-step explanation:

Both inequalities include the "or equal to" case, so both boundary lines will be solid. That excludes choices A and D.

The first inequality is plotted the same way in all graphs, so we must look at the second inequality. The relationship of y and the comparison symbol is ...

  -y ≥ (something)

If we multiply by -1, we get ...

  y ≤ (something else)

This means the solution space will be <em>on or below (less than or equal to) the boundary line</em>. This is the shaded area in graph C. (Graph B shows shading <em>above</em> the line.)

___

<em>Further comment</em>

Since the boundary for the second inequality is fairly steep, "above" and "below" the line can be difficult to see. Rather, you can consider the relationship of x to the comparison symbol. For the second inequality, that is ...

  x ≥ (something)

indicating the solution space is <em>on or to the right of the boundary line</em>.

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Delvig [45]

Answer:

After 1 second, the ball will reach a maximum height of 16 feet

Step-by-step explanation:

The height of the ball after t seconds: h(t) = -16t^2 + 32t

The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola

t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second

then

h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16

After 1 second, the ball will reach a maximum height of 16 feet

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2 years ago
Find the slope of the line passing through the points (-3, 7) and (2. –6).
Trava [24]
The slope is -13/5.
To find this you subtract the two y and get -13. You then do this with the x of the same two points and get -5. So the answer is -13/5, and you simplify if possible.
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3 years ago
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nexus9112 [7]
\displaystyle\int_0^5R(t)\,\mathrm dt\approx\sum_{i=1}^4\frac{R(t_i)+R(t_{i-1})}2\Delta t_i

where t_0=0,t_1=1,t_2=2,t_3=4,t_4=5, and we define \Delta t_i=t_i-t_{i-1} for i\ge1. The sum is adding up the areas of several trapezoids, each with dimensions determined by the values of t_i and R(t_i). (See the picture below)

So the number of deliveries made is approximately

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Show that if x, y, z are integers such that x^3+5y^3 = 25z^3, then x = y = 0.
Gre4nikov [31]

Answer:

3125*k^9 + y^3 is an integer my closure property.

 but 5^(1/3) is not an integer, which forces z to be irrational.

Note that there is no way an integer value can rationalize 5^(1/3)

Step-by-step explanation:

x^3 = 25z^3 - 5y^3

x^3 = 5 ( 5z^3 - y^3)

x  =  (5 ( 5z^3 - y^3) )^(1/3) must be an integer

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Then  (5z^3 - y^3)^(1/3) = 25*k^3 for some integer k

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z =  ( 3125*k^9 + (1/5)*y^3 )^ ( 1/3)

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