Answer:
After 1 second, the ball will reach a maximum height of 16 feet
Step-by-step explanation:
The height of the ball after t seconds: h(t) = -16t^2 + 32t
The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola
t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second
then
h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16
After 1 second, the ball will reach a maximum height of 16 feet
The slope is -13/5.
To find this you subtract the two y and get -13. You then do this with the x of the same two points and get -5. So the answer is -13/5, and you simplify if possible.

where

, and we define

for

. The sum is adding up the areas of several trapezoids, each with dimensions determined by the values of

and

. (See the picture below)
So the number of deliveries made is approximately
Answer:
3125*k^9 + y^3 is an integer my closure property.
but 5^(1/3) is not an integer, which forces z to be irrational.
Note that there is no way an integer value can rationalize 5^(1/3)
Step-by-step explanation:
x^3 = 25z^3 - 5y^3
x^3 = 5 ( 5z^3 - y^3)
x = (5 ( 5z^3 - y^3) )^(1/3) must be an integer
= 5^(1/3) * (5z^3 - y^3)^(1/3)
Then (5z^3 - y^3)^(1/3) = 25*k^3 for some integer k
5z^3 - y^3 = 15625*k^9
5z^3 = 15625*k^9 + y^3
z^3 = 3125*k^9 + (1/5)*y^3
z = ( 3125*k^9 + (1/5)*y^3 )^ ( 1/3)