Question

Jim needs to rent a car. A rental company charges $21.00 per day to rent a car and $0.10 for every mile driven.

Answer 1

Answer:

$21d+25\leq 115$

Max is 4 days.

Step-by-step explanation:

An inequality is a math statement with more the one solution. The solution has a range of values for which the inequality can be satisfied. It has the same following components as an equation: variables and operations. However, the equal sign is replaced by an inequality sign: $,\leq,\geq$.

We start by choosing a variable for an unknown value. Here is it the number of days he rents the car. We choose d.

We know he rents it for $21 pr day or 21d for any number of days. We also know her will drive 250 miles at $0.10 per mile or 0.10(250). We will combine the two into an expression.

21d + 0.10(250)

We know his limit is $115. This means he can rent the car for any number of days until he reaches $115. The charge must be less than or equal to 115.

So we write $21d+0.10(250)\leq 115$.

To find the number of days he can rent the car, we solve for d using inverse operations.

$21d+0.10(250)\leq 115\\21d+25\leq 115\\21d+25-25\leq 115-25\\21d\leq 90\\\frac{21d}{21} \leq \frac{90}{21}\\d\leq 4.3$

This means Jim can rent the car up to 4 days. The 5th day will put the cost over $115.