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fenix001 [56]
3 years ago
13

Jim needs to rent a car. A rental company charges $21.00 per day to rent a car and $0.10 for every mile driven.

Mathematics
1 answer:
Ulleksa [173]3 years ago
3 0

Answer:

21d+25\leq 115

Max is 4 days.

Step-by-step explanation:

An inequality is a math statement with more the one solution. The solution has a range of values for which the inequality can be satisfied. It has the same following components as an equation: variables and operations. However, the equal sign is replaced by an inequality sign: ,\leq,\geq.

We start by choosing a variable for an unknown value. Here is it the number of days he rents the car. We choose d.

We know he rents it for $21 pr day or 21d for any number of days. We also know her will drive 250 miles at $0.10 per mile or 0.10(250). We will combine the two into an expression.

21d + 0.10(250)

We know his limit is $115. This means he can rent the car for any number of days until he reaches $115. The charge must be less than or equal to 115.

So we write 21d+0.10(250)\leq 115.

To find the number of days he can rent the car, we solve for d using inverse operations.

21d+0.10(250)\leq 115\\21d+25\leq 115\\21d+25-25\leq 115-25\\21d\leq 90\\\frac{21d}{21} \leq \frac{90}{21}\\d\leq 4.3

This means Jim can rent the car up to 4 days. The 5th day will put the cost over $115.

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cluponka [151]

Answer:

Part A: No it is not a function

Part B: The equation

Part C: x = 3

Step-by-step explanation:

Part A - The table:

Input (x)    Output (y)

6                14

12               15

15               15

25              16

This is a function because it has no repeating inputs values which have alternate outputs. Each input is assigned exactly one output.

Part B - The relation y = 7x - 15 has the value y = 27 when x = 6. You can find it by substituting into the equation.

y = 7(6) -15

y = 42 - 15

y = 27

The value of the relation in the table when x = 6 is y = 14. The equation has the greater value.

Part C: To find when y = 6, set it equal to 6 and solve for x.

6 = 7x - 15

21 = 7x

3 = x

5 0
3 years ago
True or false: Removing the parenthesis from will change the result.
egoroff_w [7]

Answer:

true

Step-by-step explanation:

the steps won't be the same

4 0
3 years ago
Read 2 more answers
A warehouse is 55 yards long, 35 yards wide, and 5 yards high. What is the area of the warehouse floor? If the warehouse is fill
amid [387]

Answer:

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

Step-by-step explanation:

First we have to calculate the area, for this we must multiply the length by the width

a = area

l = long = 55yd

w = width = 35yd

a = l * w

a = 55yd * 35yd

a = 1925yd²

to calculate the volume we have to multiply the area by the height

asks us for the volume for half the height so we have to divide the height by 2

a = area = 1925yd²

h = height = 5yd/2 = 2.5yd

v = volume

v = a * h

v = 1925yd² * 2.5yd

v = 4812.5yd³

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

5 0
3 years ago
X=6{2+3[2(7-3)+(7+1)-5]} can someone help?
erma4kov [3.2K]

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3 0
3 years ago
12<br> Using side lengths only, could the triangles be similar?<br> 0.5<br> m05 1 1.5
Murljashka [212]

Answer:

\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}

Step-by-step explanation:

\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/

\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}

\text{Despite this, let's check the ratios}

\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5

\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}

8 0
3 years ago
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