Answer:
5.00
Step-by-step explanation:
if this makes sense
Step-by-step explanation:
<_____* *________>
<---|------|-----|-----|-----|-----|----->
-2 -1. 0. 1. 2. 3
Answer:
{ 6, 9, 16, 18 }
Step-by-step explanation:
To find the range substitute the values of x from the domain into the equation for y, that is
x = - 3 : y = - 3 + 9 = 6
x = 0 : y = 0 + 9 = 9
x = 7 : y = 7 + 9 = 16
x = 9 : y = 9 + 9 = 18
The y values are the range of the relation, that is
y ∈ { 6, 9, 16, 18 }
<h3>
Answer: 74</h3>
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Work Shown:
h(x) = 7x-5
h(2) = 7(2)-5
h(2) = 14-5
h(2) = 9
f(h(2)) = f(9)
f(x) = x^2-7
f(9) = 9^2-7
f(9) = 81-7
f(9) = 74
f(h(2)) = 74
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Here's a slightly alternative approach:
f(x) = x^2 - 7
f(h(x)) = ( h(x) )^2 - 7
f(h(x)) = ( 7x-5 )^2 - 7
f(h(2)) = ( 7*2-5 )^2 - 7
f(h(2)) = ( 14-5 )^2 - 7
f(h(2)) = ( 9 )^2 - 7
f(h(2)) = 81 - 7
f(h(2)) = 74
Answer:
4
Step-by-step explanation:
A coefficient is a number before the variable. The third term is 4c^3, and the coefficient is 4.
Hope this helps!
