What's the mean of 8, 17, 9, 3, 13
1 answer:
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Answer:
Options (1), (3), and (4)
Step-by-step explanation:
Since, slope of a line passing through two points and
is given by,
m =
Therefore, slope of a line passing through (0, 5) and (2, 8) will be,
m = = 1.5
Equation of line passing through (x', y') and slope 'm' is,
y - y' = m(x - x')
Therefore, equation of a line passing through (0, 5) and slope = 1.5,
y - 5 = 1.5(x - 0)
y = 1.5x + 5
Since, all the points which lie on this line will satisfy this equation.
For (4, 11),
11 = 1.5(4) + 5
11 = 11
Point (4, 11) lies on this line.
Point (5, 10)
10 = 1.5(5) + 5
10 = 7.5 + 5
10 = 12.5
But 10 ≠ 12.5
Therefore, (5, 10) doesn't line on the line.
Point (6, 14)
14 = 1.5(6) + 5
14 = 14
True.
Therefore, (6, 14) lies on the line.
Point (30, 50)
50 = 1.5(30) + 5
50 = 50
True.
Therefore, (30, 50) lies on the line.
Point (40, 60)
60 = 1.5(40) + 5
60 = 65
But 60 ≠ 65
Therefore, (40, 60) doesn't lie on the line.
Options (1), (3) and (4) and the correct options.
32 × 2 = 68
32 × 3 = 96
32 × 4 = 128
So far we can conclude that the answer to your question lies somewhere between the numbers 3 and 4. To narrow down the answer some more, multiply 32 by 3.5 (a midway point between 3 and 4).
32 × 3.5 = 112
The number 112 tells us that the decimal we are looking for is higher than 3.5. (Because we need to get to 125, not 112.) Let's try some decimals between 3.5 and 4.
32 × 3.7 = 118.4
32 × 3.8 = 121.6
32 × 3.9 = 124.8
32 × 4 = 128
As we narrow down our answer, we can see that the number we are looking for lies between 3.9 and 4 on the number line. Now we need to start testing some decimals between 3.9 and 4.
32 × 3.905 = 124.96
Again, use the number five as a "midway" point to decide if you should use numbers that are higher or lower than 3.905. In this case, we need to use numbers higher than 3.905.
32 × 3.906 = 124.992
32 × 3.907 = 125.024
We are getting even closer to our number now that we know the decimal is somewhere between 3.906 and 3.907.
32 × 3.9065 = 125.008
With our midway point we can see that our number lies between 3.906 and 3.9065. Let's try a quarter point to see where our number lies from there.
32 × 3.90625 = 125
And BINGO! We have found the answer to the question. To be rephrased, our answer can be put like this:
= 3.90625
32 × 3 = 96
32 × 4 = 128
So far we can conclude that the answer to your question lies somewhere between the numbers 3 and 4. To narrow down the answer some more, multiply 32 by 3.5 (a midway point between 3 and 4).
32 × 3.5 = 112
The number 112 tells us that the decimal we are looking for is higher than 3.5. (Because we need to get to 125, not 112.) Let's try some decimals between 3.5 and 4.
32 × 3.7 = 118.4
32 × 3.8 = 121.6
32 × 3.9 = 124.8
32 × 4 = 128
As we narrow down our answer, we can see that the number we are looking for lies between 3.9 and 4 on the number line. Now we need to start testing some decimals between 3.9 and 4.
32 × 3.905 = 124.96
Again, use the number five as a "midway" point to decide if you should use numbers that are higher or lower than 3.905. In this case, we need to use numbers higher than 3.905.
32 × 3.906 = 124.992
32 × 3.907 = 125.024
We are getting even closer to our number now that we know the decimal is somewhere between 3.906 and 3.907.
32 × 3.9065 = 125.008
With our midway point we can see that our number lies between 3.906 and 3.9065. Let's try a quarter point to see where our number lies from there.
32 × 3.90625 = 125
And BINGO! We have found the answer to the question. To be rephrased, our answer can be put like this: