Question

The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is 35 hours and the median is 31.2 hours. Twenty-four of the families in the sample turned on the television for 20 hours or less for the week. The 6th percentile of the data is 20 hours.
Step 1 of 5: Based on the given information, determine if the following statement is true or false.The 56th percentile is less than 30 hours.

Step 2 of 5: Approximately how many families are in the sample? Round your answer to the nearest integer.

Step 3 of 5: Based on the given information, determine if the following statement is true or false. Approximately 200 families turned on their televisions for less than 35 hours.

Step 4 of 5: What is the value of the 50th percentile?

Step 5 of 5: Based on the given information, determine if the following statement is true or false.The first quartile is greater than or equal to 20 hours.

Answer 1

Answer:

Multiple Answers

Step-by-step explanation:

We know that the mean is 35 and the median is 31.2 hours.

• Step 2: If we clear n of the percentil formule of the 6th percentile:

   (n)($\frac{6}{100}$)=  24 families   →     n=400 families.

• Step 3: true. The half of the population is 200. Therefore the 50% of the sample(the 50th percentile) is under or equal 31.2

• Step 4: By definition the median is the 50th percentil. So the 50 percentil   →     31.2.

• Step 1: If we considerate that the 50th percentil is 31.2, a bigger percentil had to be bigger too.

• Step 5: False. At the beggining we have that the 6% of the population were below or equal to 20 hours, therefore the 25% of the data have to be greater or equal to 20.