Let the cost of one sheep and one cow be x and y respectively.
Therefore,
5x+5y=129
10x+17y =177
Solving the two equations,
Multiply the first equation by 2 and subtract the second from the results;
10x+10y = 258
10x+17y = 177
0x-7y = 81 => y= $-11.57 (cannot be a negative value). The details of the question need to be checked.
Now,
5x+5y = 129 => 5x-57.86 =129=>5x = 186.86 => x= $37.37
The area would be 9 because the perimeter of the regular quadrilateral would be 3 and if you multiply 3 by 3 you have 9.
N would be the variable that we are solving for.
Lets solve:-
n * 3.25 = 325
3.25/3.25 = 325/3.25
n = 100
Answer: n = 100
Answer:
Purchases greater than 66.67 dollars should use coupon 2, while purchases between 20 dollars and 66.67 should use coupon 1.
Step-by-step explanation:
Coupon 1 must be used as long as those 10 dollars represent more money than 15% of coupon 2.
For example, if the purchase is the minimum of $ 20, 10 dollars represents half of the purchase, therefore in this case it is better to use coupon 1.
In this case, coupon 2 would only be a discount of 3 dollars (20 * 0.15).
So when from what value would it be better to use coupon 2, it would have to be calculated when it is worth more than 10 dollars.
10 = x * 0.15
x = 10 / 0.15
x = 66.67
That is to say that from the purchases greater than 66.67 dollars, coupon 2 would have a discount equivalent to 10 dollars or more.
