Find the set of outcomes that occur when we flip 3 coins and obtain more heads than tails .

1 answer:

8 0

If we flip 3 coins, the 8 possible outcomes are:
{HHH},
{HHT};
{HTH};
{HTT};
{THH};
{THT};
{TTH};
{TTT};
Which of the 8 outcomes have more heads than tails?

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Find the first 5 terms of the arithmetic sequence : a(1)=-3 , a(17)=-20

madreJ [45]

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an=a+(n-1)d
where:
a=first term
d=common difference
given:
a3=22
a(17)=-20
substituting this in our equation we get:
22=a+(3-1)d
22=a+2d
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also:
-20=a+(17-1)d
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but substituting i in ii we get:
-20=22-2d+16d
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d=-3
but:
a=22-2d
a=22-2(-3)
a=28
thus the formula will be:
an=28-3(n-1)
thus the first term will be 28
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a2=28-3(2-1)
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the 3rd term will be:
a3=28-3(3-1)
a3=28-6
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a5=28-3(5-1)
a5=28-3(4)
a5=28-12
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Answer:

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<h2>Explanation:</h2>

Here we have the following expression:

$(csc x - 1) (csc x + 1)$

So we need to extend this. Remember that the difference of squares tells us:

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