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2 years ago

13

For the model to be to scale, the ratio of the height to the side length should be the same for both the actual pyramid and the

model. Is the model of Khufu’s pyramid to scale? If not, is it close?

2 answers:

Alex787 [66]2 years ago

8 0

Answer: yes it’s close

Step-by-step explanation:

lidiya [134]2 years ago

6 0

Answer:

Do you have a picture of the question so we can see the pyramid?

Step-by-step explanation:

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Zen Garden Café uses 9

anyanavicka [17]

72g of tea .

Working:

9:36
X=288

Cross multiply :
36x= 288/9
= 36x= 2592
= 2592/36 = 72

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2 years ago

PLEASE HELP WILL GIVE THE FIRST PERSON TO ANSWER BRAINLIEST!! In a target shooting contest, contestants receive 5 points for hit

vekshin1

Answer:

Tom hit 13 red targets!

Step-by-step explanation:

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2 years ago

Read 2 more answers

Plot two points that are 777 units from Point \blueD{D}Dstart color #11accd, D, end color #11accd and also share the same xxx-co

Karolina [17]

Right format of question:

Plot two points that are 7 units from Point D and also share the same x-coordinate as Point D.

Answer:

$D' = (-4,-6)$ and $D' = (-4,8)$

Step-by-step explanation:

Given

$D(x,y) = (-4,1)$

Required

Determine a point 7 points from D and in the same x coordinate

Represent this point with D'.

From the requirement of the question, D' has two possible values and these values are:

$D' = D(x,y-7)$ ----> 7 units down and

$D' = D(x,y+7)$ ----> 7 units up

Substitute values for x and y in $D' = D(x,y-7)$ and $D' = D(x,y+7)$

So, we have:

$D' = D(x,y-7)$

$D' = (-4,1 - 7)$

$D' = (-4,-6)$

$D' = D(x,y+7)$

$D' = (-4,1+7)$

$D' = (-4,8)$

3 0

3 years ago

Write the monomial in standard form. name it's coefficient and identify its degree.

Hunter-Best [27]

Answer:

$Standard\ Form = {3n^2} m^{-2}$

Step-by-step explanation:

Given

$\frac{2}{3m^2n} * 4.5n^3$

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

$\frac{2}{3m^2n} * 4.5n^3$

$Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}$

Split the numerator and the denominator

$Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}$

Multiply Like terms

$Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}$

Divide 9 by 3 to give 3

$Standard\ Form = \frac{3 * n^3}{m^2 * n}$

Divide n³ by n to n²

$Standard\ Form = \frac{3 * n^2}{m^2 }$

Split fraction

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$

From laws of indices;

$\frac{1}{a^n} = a^{-n}$

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$ becomes

$Standard\ Form = {3 * n^2} * m^{-2}$

Multiply all together

$Standard\ Form = {3n^2} m^{-2}$

5 0

2 years ago

X^2 - y^2 = 100

luda_lava [24]

Answer:

20

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

$x+y=5$

Subtract y from both sides:

$x=5-y$

Now, substitute "5-y" for "x" in the first equation:

$(5-y)^2-y^2=100$

Note that:

$(a-b)^2=a^2-2ab+b^2$

$25-10y+y^2-y^2=100$

Cancel out like terms:

$25-10y=100$

Subtract 25 from both sides:

$-10y=75$

Divide both sides by -10

$y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}$

Now, substitute this value back into either of the equations to solve for x.

$x+y=5\\x-\frac{15}{2}=5\\$

Add 15/2 to both sides:

$x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}$

Now, find the difference:

$x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20$

8 0

2 years ago