The segments below shown below could form a triangle

How to get from 92 to 280 in 4 jumps. This is supposed to be an exponential equation. You have to multiply the same number every

bogdanovich [222]

The exponential function is
f(x)=ab^x, where b is the base, the number to multiply every time x is increased by 1.

If f(x)=92, f(x+4)=280, then
f(x+4)/f(x) = 280/92 = ab^(x+4)/(ab^x) = b^4
to find the base b,
b^4=(280/92)
b=(280/92)^(1/4) ..... fourth root, or take square-root twice
=3.4035^(1/4)
=1.3208 (accurate to 4 places of decimal).

Edit: 92*1.3208^4 gives 279.9858 (missing little bit because of accuracy).
A slightly better accuracy would be
base = 1.320816698856163
and 92*1.320816698856163^4 would still be 279.9999999999993, but VERY close to 280.
So it all depends on the accuracy you need.
If you need more accuracy, please tell me how many accurate digits you'd like the results.
Here it is:
base = 1.320816698856163713875997666455513013800337299231824403890097792042432005288739246325005446716740
and if you multiply together
92*base^4, you will get 280 accurate to at least 90 digits after the decimal.
I think that should be sufficient for what you need. Recall that these calculations cannot be done or verified on a 10 or 12 digit calculator.

Well, to please you, I have calculated it to 500 digits, don't think that's going to be of much practical use for anybody.
By the way, that's as far as I will do this evening. My eyes are almost closing!

base=1.3208166988561637138759976664555130138003372992318244038900977920424320052887392463250054467167408005624428737585147309981331510076693180633495574937759374668399829195521733208637815593771220504215429477168159456265024711237470736388371979840461777898466419772297172931568429339640964205400234392902077320257671263508487367942846685479533507498695981037274512050120058009244868634949261015429944340565311559486391625531554216085859773912355361847787636892603324966350039688974359584811585283183726532

8 0

3 years ago

I'm giving brainliest to the most helpful answer. For 50 points:

Alenkinab [10]

Answer:

1) $\displaystyle\frac{5}{18}\approx27.78\%$

2) $\displaystyle\frac{4}{7}\approx57.14\%$

3) $\displaystyle \frac{13}{16}=81.25\%$

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%$

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

$\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%$

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

$\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%$

4 0

3 years ago

The triangles are congruent by SSS and HL. Triangles R S T and V W X are shown. Triangle R S T can be rotated about point S and

NikAS [45]

Answer:

rotation then translation

9 0

3 years ago

Read 2 more answers

Pound of saffron, but the ordering system wants a decimal. What

Ira Lisetskai [31]

Answer:

Step-by-step explanation:

c. 1.04 Double check though, because i'm not exactly sure

5 0

3 years ago

A woman 5 ft tall walks at the rate of 7.5 ft/sec away from a streetlight that is 10 ft above the ground. At what rate is the ti

lesya [120]

Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.

8 0

3 years ago