What is the area of a sector with a central angle of 210 degrees and a diameter of 4.6 m? Round the answer to the nearest tenth.

Please answer the questions fast please

Sergeu [11.5K]

Answer:

1.400000

2.138400

3.6,12,18,24

4.85600

5.900000

6. 8.25kg

7.lxxv

8.60

9.1,2,4,5,10,20

10.5

4 0

3 years ago

At the end of each quarter, Patti deposits $500 into an account that pays 12% interest compounded quarterly. How much will Patti

SVEN [57.7K]

Answer:

a.$7,096

Step-by-step explanation:

total amount A = s(\frac{(1+\frac{r}{n}) ^{n*t}-1 }{\frac{r}{n} } )[/tex]

[this is the formula used when certain amount is added at regular intervals and if the interest is COMPOUNDED]

(here,

s=deposit added at the end of each quarter= $500

n= number of times interest is compounded per unit 't'=4

t=total time = 3 years

r=interest rate ( expressed in decimal or fraction not in %) = 12/100 = 0.12 )

A= 500(\frac{(1+\frac{0.12}{4}) ^{4*3}-1 }{\frac{0.12}{4} } )[/tex]

by solving further,

A $=500(\frac{(1.03) ^{12}-1 }{0.03} )\\\\=500(\frac{1.42576-1}{0.03} )\\\\=500(\frac{0.42576}{0.03}) \\=$7,096$

( [1.03]^12= 1.42576 ( approximately) { use calculator for exact values})

3 0

3 years ago

Find the area of the rectangle.

Levart [38]

<h2>Multiply 50 * 14 =700 so the answer is <em><u>700</u></em></h2><h2><em>Hope this helps!</em></h2>

6 0

3 years ago

Read 2 more answers

If points A and B are randomly placed on the circumference of a circle with a radius of 2 cm, what is the probability that the l

OLga [1]

Answer:

The probability that the length of chord AB > 2 cm is 2/3 ⇒ D

Step-by-step explanation:

* Lets explain how to solve the problem

- Points A and B are randomly placed on the circumference of a

circle with a radius of 2 cm

- We need to find the probability that the length of chord AB is

greater than 2 cm

<em>- </em>Probability = required length of arc / circumference

- <em>Assume that the length of the chord AB is 2 and the center of </em>

<em> the circle is labeled M</em>

- The radius of the circle is 2 and AB = 2

- In Δ AMB

∵ MA= MB = 2 radii

∵ AB = 2

∴ Δ AMB is an equilateral triangle

∴ m∠AMB = π/3

∵ The length of an arc = r Ф , where r is the radius of the circle and

Ф is the central angle subtended by this arc

∵ r = 2 , Ф = π/3

∴ The length of arc AB = 2 × π/3 = 2π/3

- The arc AB is in the half of the circle then there are another arc

with the same length in the other half of the circle

- The length of the arc we must excluded from the length of the

circle to have the part of length of AB is greater than 2 is

2(2π/3) = 4π/3

∴ The length of the excluded arc is 4π/3

∵ The length of the circle is 2πr

∵ r = 2

∴ The length of the circle = 2π(2) = 4π

- <em>The required arc = length circle - length excluded arc</em>

∵ The length of the excluded arc = 4π/3

∵ The length of the circle = 4π

∴ The required arc = 4π - 4π/3 = 8π/3

- <em>Probability = required length of arc / circumference</em>

∴ Probability = (8π/3)/(4π) = 2/3

∴ The probability that the length of chord AB > 2 cm is 2/3

4 0

3 years ago

A flag pole has a rope that attaches to the ground from the top of the flagpole the rope create a 30° angle with the ground and

OLEGan [10]

Answer:

$5.77\ \text{m}$

$11.54\ \text{m}$

Step-by-step explanation:

p = Height of pole

h = Length of role

b = Distance between the bottom of the rope and bottom of the pole = 10 m

$\theta$ = Angle between the rope and the ground = $30^{\circ}$

$\tan\theta=\dfrac{p}{b}\\\Rightarrow p=b\tan\theta\\\Rightarrow p=10\tan30^{\circ}\\\Rightarrow p=5.77\ \text{m}$

The length of the rope is $5.77\ \text{m}$

$\cos\theta=\dfrac{b}{h}\\\Rightarrow h=\dfrac{b}{\cos\theta}\\\Rightarrow h=\dfrac{10}{\cos30^{\circ}}\\\Rightarrow h=11.54\ \text{m}$

The length of the pole is $11.54\ \text{m}$

3 0

3 years ago