What is the area of parallelogram RSTU?
2 answers:
First, we circumscribe a rectangle about the parallelogram as shown in the figure. The size of this rectangle is 10 by 6 clearly.
Between the rectangle and the parallelogram 4 triangles are formed, 2 by 2 congruent. We are going to remove the area of these 4 triangles from 60 (the area of the rectangle) and thus get the area of the parallelogram.
Note that one of the triangles has side lengths 4; 4. Thus, the area of this triangle is (4*4)/2=16/2=8 (square units.)
Each of the other two non-congruent triangles to the above have sides of length 6;2, so the area of each is (6*2)/2 =6 (square units.)
Thus, the area of the parallelogram is 60-8-8-6-6=60-16-12=60-28=32 (square units.)
Answer: 32 (square units.)
Between the rectangle and the parallelogram 4 triangles are formed, 2 by 2 congruent. We are going to remove the area of these 4 triangles from 60 (the area of the rectangle) and thus get the area of the parallelogram.
Note that one of the triangles has side lengths 4; 4. Thus, the area of this triangle is (4*4)/2=16/2=8 (square units.)
Each of the other two non-congruent triangles to the above have sides of length 6;2, so the area of each is (6*2)/2 =6 (square units.)
Thus, the area of the parallelogram is 60-8-8-6-6=60-16-12=60-28=32 (square units.)
Answer: 32 (square units.)
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Answer:
Check attachment for solution
Step-by-step explanation:
<span>First thing you'll need to know is that the value for this equation is actually an approximation 'and' it is imaginary, so, one method is via brute force method.
You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in </span><span>signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...
The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so </span>
<span> where 'n' is the number you approximate, like n=0,1,2... etc. f(y) would the equation, and f'(y) is the derivative of f(y), now what you'll need to do is substitute the 'n' values into 'y' to find the approximation.</span>
You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in </span><span>signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...
The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so </span>