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3 years ago

(3x5 y2)(6x3y7) simplify

Mathematics

2 answers:

Feliz [49]3 years ago

5 0

Answer:

15y

Step-by-step explanation:

vladimir2022 [97]3 years ago

4 0

Answer:

(1): "x7" was replaced by "x^7". 1 more similar replacement(s).

Equation at the end of step 1

(0 - (3 • (x5))) • (2•3x7)

Equation at the end

(0 - 3x5) • (2•3x7)

Multiplying exponential expressions

3.1 x5 multiplied by x7 = x(5 + 7) = x12

Multiplying exponents:

3.2 31 multiplied by 31 = 3(1 + 1) = 32

Final result :

( -32•2x12)

Step-by-step explanation:

You might be interested in

How do i multiply 4000x by the square root of 42

Masteriza [31]

Answer:

25922.963

Step-by-step explanation:

the square root of 42 is 6.48074069841

4000*6.48074069841 is 25922.9627936

8 0

2 years ago

BRAINLYEST TO WHO EVER IS RIGHT!!!

Genrish500 [490]

Answer: -x because its more than one zero

Step-by-step explanation:

4 0

3 years ago

An electronics company produces transistors, resistors, and computer chips. Each transistor requires 3 units of copper, 2 unit

Gala2k [10]

Answer:

475 transistors, 25 resistors and 50 computer chips can be produced.

Step-by-step explanation:

Let us consider, p = Number of transistors.

q = Number of resistors.

r = Number of computer chips.

The following three linear equations according to question,

$3\times p + 3\times q + 2\times r = 1600\\2\times p + 1\times q + 1\times r = 1025\\1\times p + 2\times q + 2\times r = 625$

The matrix form of any system, Ax = B

Where, A = Coefficient matrix

B = Constant vector

x = Variable vector

$A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right], x = \left[\begin{array}{ccc}p\\q\\r\end{array}\right], B = \left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]$

The inverse matrix, $A^{-1}$ can be found by using the following formula,

$A^{-1} = \frac{1}{det A}\times (C_{A}) ^{T}$

Where, det A = Determinant of matrix A.

$C_{A}$ = Matrix of cofactors of A

Now, applying this formula to find $A^{-1}$ ;

$det A = \left[\begin{array}{ccc}3&3&2\\2&1&1\\1&2&2\end{array}\right] = 3\times(2-2)-3\times(4-1)+2\times(4-1) = -3$

Here, $det A\neq 0$ , thus the matrix is invertible.

$C_{A} = \left[\begin{array}{ccc}(2-2)&-(4-1)&(4-1)\\-(6-4)&(6-2)&-(6-3)\\(3-2)&-(3-4)&(3-6)\end{array}\right] = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] \\(C_{A}) ^{T} = \left[\begin{array}{ccc}0&-3&3\\-2&4&-3\\1&1&-3\end{array}\right] ^{T} = \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]$

$A^{-1} = \frac{1}{-3}\times\left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right] \\ So, x= \frac{1}{-3} \left[\begin{array}{ccc}0&-2&1\\-3&4&1\\3&-3&-3\end{array}\right]\times\left[\begin{array}{ccc}1600\\1025\\625\end{array}\right]= \frac{1}{-3} \left[\begin{array}{ccc}-1425\\-75\\-150\end{array}\right] = \left[\begin{array}{ccc}475\\25\\50\end{array}\right]$

So, p = 475, q = 25, r = 50.

7 0

3 years ago

Nth term of the following sequence.<br> 9. 14, 19, 24,

wolverine [178]

(5) you need to subtract 19 from 25 or
9 plus x the number to get 14

6 0

3 years ago

How many whole numbers are there between 30 and 79?

Svetllana [295]

Answer:

Step-by-step explanation:

<u>Definition of whole number: </u>Whole numbers are a set of numbers including the set of natural numbers (1 to infinity) and the integer '0'

The formula for finding the number of whole numbers between to given numbers “m” and “n” (assuming that “m” and “n” are included in the listing, and that “n” is the larger value) is:

(n - m) + 1

And the formula gives:

(79 - 30) + 1 = 49 + 1 = 50

8 0

2 years ago