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stich3 [128]
3 years ago
5

the vertex of a quadratic function is (6, 2), and the y-intercept of the function is (0, −70). the equation of the function in v

ertex form, f(x) = a(x - h)2 k, is shown. –70 = a(0 – 6)2 2 what is the value of a?
Mathematics
2 answers:
Kamila [148]3 years ago
6 0

<u>Answer-</u>

<em>The value of a is </em><em>-2</em>

<u>Solution-</u>

The vertex form of parabola-

y=a(x-h)^2+k

Where, vertex is at (h, k)

Given that the vertex is at (6, 2), so equation would be

y=a(x-6)^2+2

As the y intercept is the point which lies on the parabola, so it must satisfy the parabola equation.

\Rightarrow -70=a(0-6)^2+2

\Rightarrow -70-2=a(-6)^2

\Rightarrow a(6)^2=-72

\Rightarrow 36a=-72

\Rightarrow a=-2

My name is Ann [436]3 years ago
5 0
Hello,
++++++++++++++++
f(x)=a(x-6)²+2
f(0)=-70==>a(-6)²+2=-70===>36a=-72==>a=-2
++++++++++++++++++++

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3 0
3 years ago
7y-3x= -5 solve for x
nika2105 [10]
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7 0
3 years ago
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3 0
3 years ago
Read 2 more answers
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kkurt [141]
The third one is a point with the first equation.

I had to simplify the second equation.

It simplified to,

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4 0
3 years ago
Somebody help me with this? Please
defon

Answer:

See the attached image for solutions.

Step-by-step explanation:

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<u />

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Hope this helps! :)

6 0
2 years ago
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