Answer:
there is no collision between the particles
Step-by-step explanation:
for the first particle
x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π
for the second particle
x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π
then for the collision
x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t
y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2
since 1/3 ≠ 2 there is no collision between the particles
Answer:
1) 
- Greater than -10 and less than 10.
2) ![[-10, 10]](https://tex.z-dn.net/?f=%5B-10%2C%2010%5D)
- Greater than or equal to -10 and less than or equal to 10.
3) 
- Greater than or equal to -10 and less than 10.
4) ![(-10, 10]](https://tex.z-dn.net/?f=%28-10%2C%2010%5D)
Greater than -10 and less than or equal to 10.
Step-by-step explanation:
There are four form of describing that set in interval notation, which presented below:
1) - Greater than -10 and less than 10.
2) - Greater than or equal to -10 and less than or equal to 10.
3) - Greater than or equal to -10 and less than 10.
4) Greater than -10 and less than or equal to 10.
We are given a watermelon dropped at free fall from a building 320 meters above the sidewalk. Superman is headed down at 30 meters per second. We are asked to determine how fast is the watermelon going when it passes Superman. To solve for the final velocity of the watermelon, we will use one of the kinematic equations (free fall):
vf = vi + a*t
where vf is the final velocity
vi is the initial velocity, zero
a is the acceleration, in this case, gravitational acceleration = 9.8m/s^2
t is time
we also need to set-up another equation using the distance:
d = vf + vi / 2 * t
(1) 320 m = vf * t /2
(2) vf = 9.8 m/s^2 * t
From here, we have two equations and two unknown, thus we can solve the problem by substitution.
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10 because you know that the decimal moves one to the left if you are dividing by ten and one to the right if you are multiplying by ten.
Check your work. 0.32 divided by 10 is 0.032
