Bluetooth is the most reasonable answer
Answer:
In Python:
year = int(input("Year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("Leap year")
else:
print("Not a leap year")
else:
print("Leap year")
else:
print("Not a leap year")
Explanation:
This line prompts user for year
year = int(input("Year: "))
This condition checks if input year is divisible by 4
if (year % 4) == 0:
If yes, this condition checks if input year is divisible by 100
if (year % 100) == 0:
If yes, this condition checks if input year is divisible by 400
if (year % 400) == 0:
If divisible by 4, 100 and 400, then it is a leap year
print("Leap year")
else:
If divisible by 4 and 100 but not 400, then it is not a leap year
print("Not a leap year")
else:
If divisible by 4 but not 100, then it is a leap year
print("Leap year")
else:
If it is not divisible by, then it is not a leap year
print("Not a leap year")
No. It is not impossible to understand and make this algorithm a success. It may only take a longer duration to reach success but it does not that it is impossible. Problems may become more difficult to understand and debug but there is enough time, duration, resources and support, the algorithm can be developed.
Answer:
freezing action photographer i think this is the type.... i don't know much about photography yet
Explanation:
The answer is application group.
