H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
Answer:
The distribution is skewed, so use the five-number summary. range: 38, median: 16, half of the data are between 9.5 and 25
Step-by-step explanation:
In the picture attached the histogram is shown. We can see that data is skewed to the right, so we have to use the five-number summary. The range of the data is 39 - 1 = 38 (subtraction of the maximum value to the minimum value); the median is (15 + 17)/2 = 16 (if you order the values, 15 and 17 are in the middle); quartile 1 is 9.25 and quartile 3 is 25.5 (see diagram of box and whisker attached), then half of the data are between those values.
Answer:
x=7.5 y y=12.99
Step-by-step explanation:
i will try again if this is wrong
Answer:
the answer is d. What is the width of the box, in inches, that
produces the maximum volume?
Step-by-step explanation:
length: 120 - 6w >
Answer:
the answer is b
Step-by-step explanation:
