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Ivenika [448]
3 years ago
5

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t)

= -4.9t2 +19.6t + 58.8. What is the object's maximum height?
Mathematics
1 answer:
beks73 [17]3 years ago
5 0
H(t) = Ho +Vot - gt^2/2

Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2

H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2

Maximun height is at the vertex of the parabole

To find the vertex, first find the roots.

58.8 + 19.6t - 4.9t^2 = 0

Divide by 4.9

12 + 4t - t^2 = 0

Change sign and reorder

t^2 - 4t -12 = 0 

Factor

(t - 6)(t + 2) =0 ==> t = 6 and t = -2.

The vertex is in the mid point between both roots

Find H(t) for: t = [6 - 2]/2 =4/2 = 2

 Find H(t) for t = 2

H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4

Answer: the maximum height is 78.4 m
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Hope it helps

have a great day

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I buy a MP3 player for £40 in a sale where it was 20% off. What was the original price
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A bicycle wheel has a circumference of 62 inches. Find the diameter of the wheel. If necessary, round to the tenths place. A. 39
san4es73 [151]

Answer:

The answer to your question is        diameter  = 19.7 in

Step-by-step explanation:

Data

Circumference = 62 in

diameter = ?

Process

1.- Write the formula of Circumference, remember that circumference = perimeter.

    Perimeter = 2πr

2.- Equal the equation to the value given

                        2πr = 62

-Solve it for r

                            r = 62/2(3.14)

-Result

                           r = 62/6.28

                           r = 9.87 in

3.- Find the diameter

             diameter = 2r

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