All categories

4 years ago

Round 8.54 to the nearest tenth

Mathematics

2 answers:

olchik [2.2K]4 years ago

7 0

The nearest tenth means 1 decimal place.
so the answer is 8.5

Luden [163]4 years ago

7 0

If it is 4 and less i.e. stay the same. If it is 5 and bigger you add 1. So you keep 5 the same. The answer is 8.5

You might be interested in

Ann has 30% less money than Mary, and Jessica has 70% more than Mary. If the 3 of them have a (added up) total of $102, how much

Roman55 [17]

Let x be the amount of Ann money, y be Jessica's money and z Mary money.
30% of z equates 0.3*z.
Ann has 30% less than z so: x = z - 0.3z = 0.7z.
70% of z equates 0.7z.
"Jessica has 70% more than Mary " we deduce the equation: y =z+0.7z= 1.7z.
Signe the total is $102, we deduce the equation x+y+z = 102.
x=0.7z and y=1.7z then 0.7z+1.7z+z=102, therefore 3.4z=102 then
z =102/3.4 = $30.
x=0.7*30= 21 and y=1.7*30=51.

Ann has $21, Mary has $30 and Jessica has $51.

3 0

4 years ago

Ms. Ortiz is painting her canoe. Two-fifths of gallon of paint covers ¼ of the canoe.

madreJ [45]

Answer: 8/5 or 1 3/5

Step-by-step explanation:

2/5 + 2/5 + 2/5 + 2/5

8/5 which is 1 3/5

6 0

3 years ago

Can someone answer this question please answer it correctly and show work please

GenaCL600 [577]

Answer:

5) C pink 6) A -1/2x + 1/4 7) D z ≥ 0

Step-by-step explanation:

5) White 1/6 = 4/24

Green 1/3 = 8/24

Pink 1/8 = 3/24

Yellow 3/8 = 9/24

6) 11/2x - 2(3x - 1/8) Distribute the -2

11/2x - 6x + 1/4 Combine like terms

-1/2x + 1/4

7) z ≥ 0

z is greater than or equal to 0

8 0

3 years ago

Read 2 more answers

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

Read 2 more answers

Can someone figure out b please

labwork [276]

Scaled by 2, side lengths are 3, 4 and 5

3 0

4 years ago