For this problem, you would use the slope formula, or m=(y2-y1)/(x2-x1). So, let's put in what we know.
The x's and y's correspond with our coordinates. So let's plug that in:
m=(6-0)/(2-0)
m=(6)/(2)
m=3
So, the slope of your line is 3.
Answer:
10
Step-by-step explanation:

Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Step-by-step explanation:
1. SAS
2. HL
3. AAS
4 AAS
Answer:
Step-by-step explanation:
7 / 54 * 27/35 =
1/2 * 1/5 =
1/10 <===