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aev [14]
3 years ago
12

First right answer FOR BOTH gets bain

Mathematics
1 answer:
lora16 [44]3 years ago
5 0
Question 7: 40. 40 is way above the other data.
Question 8: Median is 7, and the range is 12, the difference is 5.
Question 9: The first mean was 6, and it went up to 6.75. There is a 0.75 difference.
Question 10: The range increases by one.
You might be interested in
The sum of three consecutive odd numbers is one hundred and eleven. what is the smallest of the three numbers?
Firdavs [7]
35,37,39
111 divided by 3 is 37...so that is the middle number.  Two below it is 35 and 2 above it is 39 and all three would add up to 111.  So 35 is the lowest.
8 0
3 years ago
Pls answer fast my teacher is waiting!
a_sh-v [17]

Answer:

For company A, y = 24x + 42

For company B, y = 28x + 25

Step-by-step explanation:

x is the number of containers

y is the total cost

For company A, y = 24x + 42

For company B, y = 28x + 25

For the cost of both companies to be the same, then

24x + 42 = 28x + 25

28x - 24x = 42 - 25

4x = 17

x = 4.25

Mr Lycan would have to order about 4 containers so the cost would be the same from each company

4 0
3 years ago
to make 1 batch of lavender paint the ratio of cups of pink paint to cups of blue paint is 6 to 5. find two more raios of cups o
marshall27 [118]
Your ratio is 6:5

This means that it is 6/5.

You have to find a common number to either divide or multiply that can work for both the numerator and denominator.

6/5 doesn't have any common number to divide without getting a remainder

But we can multiply by a common number such as 2

6×2 = 12
5×2 = 10

= 12/10. ☆= the ratio is 12 : 10

or even by 3, =the ratio 18:15
8 0
3 years ago
Read 2 more answers
How do you simplify radical 32
EleoNora [17]
\sqrt{32}=  \sqrt{16*2}= \sqrt{16}* \sqrt{2}=4 \sqrt{2}
4 0
3 years ago
Can someone help me out with number 2?
Norma-Jean [14]
\sin255^o=\sin(300^o-45^o)=\sin300^o\cos45^o-\cos300^o\sin45^o= \\\\=- \frac{ \sqrt{3} }{2}\cdot  \frac{ \sqrt{2} }{2}- \frac{1}{2} \cdot  \frac{ \sqrt{2} }{2}=-      \frac{ \sqrt{6} }{4} -  \frac{ \sqrt{2} }{4}=  -\frac{  \sqrt{6}+\sqrt{2} }{4}

5 0
3 years ago
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