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-BARSIC- [3]
2 years ago
15

PLEASE I NEED HELP INSTANTLY I WILL GIVE BRAINLY AND THANKS

Mathematics
2 answers:
Serggg [28]2 years ago
8 0

Answer:

y=-(9/8)x+7

Step-by-step explanation:

Goryan [66]2 years ago
3 0

Answer:

so you're going to need to find the slope. in order to do that use (y2-y1)/(x2-x1)

(7-(-2))/(0-8)

simplify

9/-8

simplify -9/8

now using y=mx+b, we need to find b. so we can plug in the coordinates of (0,7) or (8,-2). let's use (8,-2) because it involves more math.  

y=mx+b

-2=(-9/8)(8)+b

multiply (-9/8) by 8 to get -9

-2=-9+b

add 9 to both sides

7=b

so our equation is now

y=-(9/8)x+7

Step-by-step explanation:

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is it possible to have three points that would not fit on the same plane 2 dimensional surface? Why or why not
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<span>No. Three points could be the three points of a triangle. Triangles are two dimensional surfaces. Therefore, any three points could exist on a two dimensional triangle.</span>
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Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t
frozen [14]

Answer:

The length of the third side of given triangle lies between 6.5 and 19.9.

Step-by-step explanation:

The law of cosine is as follows

 c^{2} =a^{2}+b^{2}+2abcos\alpha---------------1

⇒ a and b are the given sides of the triangle and c is the third side, and \alpha is the angle between a and b .

In equation 1 , the maximum and minimum values of cos\alpha are 1 and -1.

 so the value of c  lies in between

⇒ \sqrt{a^{2}+b^{2}-2ab   } and  \sqrt{a^{2}+b^{2}+2ab  }   = |a-b| and |a+b|

Given a=13.2 and b=6.7 so the the side lies in between  |13.2-6.7| and |13.2+6.7|

  so the third side lies between 6.5 and 19.9

3 0
3 years ago
Solve the right angle trig problem.
iris [78.8K]

Answer:

x = 53.6588°

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] cos∅ = adjacent over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use trig to find the missing angle.

<u>Step 2: Identify Variables</u>

<em>POV from angle x</em>

Angle = <em>x</em>

Adjacent = 16

Hypotenuse = 27

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Substitute:                    cosx° = 16/27
  2. Inverse:                         x° = cos⁻¹(16/27)
  3. Evaluate:                       x = 53.6588°
7 0
3 years ago
My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
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