A car travels at an average speed of 56 miles per hour. how many miles does it travel in 5 hours and 45 minutes?

colby has 16 jars of spices.He wants to arrange them in arrays. what arrays could he use to arrange them

Darya [45]

Answer:

He has 5 ways to arrange them in a array.

Step-by-step explanation:

colby has 16 jars of spices.He wants to arrange them in arrays.

<em>An array is a systematic arrangement of similar objects, usually in rows and columns.</em>

So, the choices he could have to form an array is the possible number of ways he can arrange them in rows and columns and in table it could be seen as:

S.no. Number of rows Number of columns

1 16 1

2 8 2

3 4 4

4 2 8

5 1 16

Hence, the number if arrays he could use to arrange them is 5.

6 0

3 years ago

Read 2 more answers

How do i find the answer for the expert problem

KengaRu [80]

By dividing it is how you do it

8 0

3 years ago

Read 2 more answers

Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3

babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

$3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3$

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable $z$ first.

Step 1: She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

$(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9$

Now, adding this to equation 1 will cancel out z terms.

$12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4$

Now, she need to make one more equation in $x\ and \ y$ .

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

$(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21$

Now, adding this to equation 2 will not cancel out z terms.

$-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20$

So, she makes mistake in step 2 as the $z$ terms are not being cancelled.

6 0

4 years ago

Read 2 more answers

Someone please help. If you could possibly show your work or tell me what you did that would be wonderful. Thanks!

alexandr1967 [171]

Start by getting all of your stuff on the same side.
(4x^2 - 1)/2y - (9y - 5)/3 - z+3y = 0

Then, move the (4x^2 - 1)/2y to the other side of the equation by subtracting it from both sides.
- (9y - 5)/3 - z+3y = -(4x^2 - 1)/2y

Next, get all your ys on the same side of the equation. To do this, multiply both sides by 2y.
2y * (- (9y - 5)/3 - z+3y ) = -(4x^2 - 1)

Simplify this out.
(-18y^2 - 10y)/3 - 2yz +6y^2 = -(4x^2 - 1)

(-18y^2 - 10y)/3 is equal to -6y^2 - 10y/3, so the equation can be rewritten as
-6y^2 - 10y/3 - 2yz +6y^2 = -(4x^2 - 1)
The 6y^2 and -6y^2 cancel eachother out and equal zero.
- 10y/3 - 2yz + 0 = -(4x^2 - 1)

Now we have to move z over. To do this, factor out a y from each term.
y(-10/3 - 2z) = -(4x^2 - 1)

Now, all we have to do is divide both sides by (-10/3 - 2z) to get
y = -(4x^2 - 1)/(-10/3 - 2z)

If we simplify this out, we will find that it is equal to
y = -3(4x^2 - 1)/(-10 - 6z) = -3(4x^2 - 1)/-2(5 + 3z) = 3(4x^2 - 1)/2(5 + 3z)
y = 3(4x^2 - 1)/2(3z + 5)

The answer is D.

5 0

3 years ago

Maria babysat for 6 hours on Tuesday, 3 hours on Thursday, and 4 hours on Saturday.

Alekssandra [29.7K]

Answer:

78.00$

Step-by-step explanation:

6 + 3 + 4 =13

13× 6.00= 78.00

7 0

3 years ago

Read 2 more answers