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3 years ago

Maria babysat for 6 hours on Tuesday, 3 hours on Thursday, and 4 hours on Saturday.

Mathematics

2 answers:

Alekssandra [29.7K]3 years ago

7 0

Answer:

78.00$

Step-by-step explanation:

6 + 3 + 4 =13

13× 6.00= 78.00

Contact [7]3 years ago

5 0

Answer:

First, convert 150% to the equivalent decimal 1.50 by dropping the percent sign and moving the decimal two places to the left. Then, multiply 9 by 1.50 to get 13.50. Maria now makes $13.50 per hour.

Step-by-step explanation:

I took the test and this is the sample answer

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For an equation to have infinitely many solutions, the solution will appear as a ______ statement.

DENIUS [597]

Answer:

true

Step-by-step explanation:

for example, when you solve an equation and you get something like 16=16, which is infinitely many solutions and is also a true statement

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3 years ago

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nexus9112 [7]

Answer:

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3 years ago

Read 2 more answers

Number 8 please can you write and equation

tigry1 [53]

8.5x + 55 = 123

You would use the formula: mx + b = y

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3 years ago

Ms. Zab gave a group of 5 students a total of 18.75 liters of water for a science experiment. If each student in the group used

wlad13 [49]

Answer: The quantity of the water received by each student = 3.75 liters.

Step-by-step explanation:

Given: Total water = 18.75 liters

Total students =5

If each student in the group used the same amount of water for their experiment, then the quantity of the water received by each student = $\dfrac{\text{Total quantity}}{\text{Total students}}$

$=\dfrac{18.75}{5}\\\\=3.75\ liters$

The quantity of the water received by each student = 3.75 liters.

4 0

2 years ago

What is the completely factored form of d4 -8d2 + 16

irinina [24]

According to Vieta's Formulas, if $x_1,x_2$ are solutions of a given quadratic equation:

$ax^2+bx+c=0$

Then:

$a(x-x_1)(x-x_2)$ is the completely factored form of $ax^2+bx+c$ .

If choose $x=d^2$ , then:

$\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm \sqrt{64-64} }{2}=4$

So, according to Vieta's formula, we can get:

$x^2-8x+16=(x-4)(x-4)= (x-4)^2$

But $x=d^2$ :

$d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2$

8 0

3 years ago