Ok so domain is all allowed numbers
look at deonomenator and don't allow any numbers that will make it zero
none
that means
domain=all real numbers
vertex
in form
y=a(x-h)^2+k
(h,k)=vertex
we have
y=-2(x+3)^2-1
h=-3
k=-1
vertex=(-3,-1)
range
the vertex opens down so max is y=-1
y≤-1
domain is all real
vertex is (-3,-1)
y≤-1
C
Answer:
(B) 26°
Step-by-step explanation:
The angle at A made by the radius and the tangent is 90°. The angle at O is the same as arc AB, 64°. The acute angles in a right triangle are complementary, so the angle at C is the complement of 64°.
∠ACB = 90° -64°
∠ACB = 26°
Answer:
the answer is
Step-by-step explanation:
the answer is
the answer is
the answer is
c
Answer:

Step-by-step explanation:
Let the equation of the perpendicular line is,
y = mx + b
where m = slope of the line
b = y-intercept
From the graph, slope of the line passing through (0, -1) and (3, 1),
m' =
m' = 
m' = 
To get the slope (m) of this line we will use the property of perpendicular lines,
m × m' = (-1)
m ×
= -1
m = 
Equation of the perpendicular line will be,

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)
0 = 
b = 
Equation of the line will be,
