If 2 sets are disjoint means they have not any common element.
Draw a rectangle & inscribe inside this rectangle 2 circles that do not intersect.
cercle₁ ∩ cercle₂ =Ф.
Their complement would be the part of the rectangle - the 2 circles
Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Answer:
(x +4)^2 -45
Step-by-step explanation:
The square of a binomial has the form ...
(x +a)^2 = x^2 +2ax +a^2
That is, the constant term (a^2) is the square of half the coefficient of the linear term: (2a/2)^2 = a^2.
To "complete the square", you add 0 in the form of the desired constant added to its opposite. Here, we want the constant for the square to be (8/2)^2 = 16. So, we can add 0 = 16 -16 to the expression:
x^2 +8x +16 -29 -16
(x^2 +8x +16) -45 . . . . group the terms that make the square
(x +4)^2 -45 . . . . rewritten after completing the square
18.0 1
- 0.4 17.0
_____ - 0.4
-------> ____
17.6
