Answer:
147,000N
Step-by-step explanation:
A1= 2m^2
A2= 0.2m^2
F2= 14,700N
Required
F1, the applied force
Applying the formula
F1/A1= F2/A2
substute
F1/2=14700/0.2
2*14700= F1*0.2
29400= F1*0.2
F1= 29400/0.2
F1=147,000N
Hence, the applied force is 147,000N
Answer: The answer is (A) ∠T.
Step-by-step explanation: Given that the polygon ABCDE is congruent to the polygon TVSRK. We are to find the corresponding angle of ∠EAB.
In the two polygons, the corresponding vertices are
A ⇒ T
B ⇒ V
C ⇒ S
D ⇒ R
E ⇒ K.
Therefore, ∠EAB, which is ∠A will correspond to ∠T.
Thus, the correct option is (A) ∠T.
Answer:
x = -1.5
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
0.2x + 1 = 1.6x + 3.1
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract 0.2x on both sides: 1 = 1.4x + 3.1
- Subtract 3.1 on both sides: -2.1 = 1.4x
- Divide both sides by 1.4: -1.5 = x
- Rewrite: x = -1.5
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitution: 0.2(-1.5) + 1 = 1.6(-1.5) + 3.1
- Multiply: -0.3 + 1 = -2.4 + 3.1
- Add: 0.7 = 0.7
Answer: A
Step-by-step explanation:
Answer:
(0,1)
Step-by-step explanation:
i just did it
